1. Marginal and Conditional Probabilities Consider the following joint distribution. Xo|X1|X₂|| P(X0, X1, X₂) 000 0.100 001 0.200 0 1 0 1 1 0 0 1 0 0.000 0.150 0.150 0 120

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Question 1 part A B and C please.

# Marginal and Conditional Probabilities

Consider the following joint distribution.

| \(X_0\) | \(X_1\) | \(X_2\) | \(P(X_0, X_1, X_2)\) |
|---------|---------|---------|-----------------------|
| 0       | 0       | 0       | 0.100                 |
| 0       | 0       | 1       | 0.200                 |
| 0       | 1       | 0       | 0.000                 |
| 0       | 1       | 1       | 0.150                 |
| 1       | 0       | 0       | 0.150                 |
| 1       | 0       | 1       | 0.120                 |
| 1       | 1       | 0       | 0.100                 |
| 1       | 1       | 1       | 0.180                 |

Calculate the following probabilities:

(a) \( P(X_0 = 1, X_1 = 0, X_2 = 1) \)

(b) \( P(X_0 = 0, X_1 = 1) \)

(c) \( P(X_0 = 1) \)

(d) \( P(X_1 = 0 \mid X_0 = 1) \)

(e) \( P(X_1 = 0, X_2 = 1 \mid X_0 = 1) \)

(f) \( P(X_1 = 0 \mid X_0 = 1, X_2 = 1) \)

# Independence

In the joint distribution from the previous problem, is \(X_0\) independent of \(X_1\)? Justify your answer.
Transcribed Image Text:# Marginal and Conditional Probabilities Consider the following joint distribution. | \(X_0\) | \(X_1\) | \(X_2\) | \(P(X_0, X_1, X_2)\) | |---------|---------|---------|-----------------------| | 0 | 0 | 0 | 0.100 | | 0 | 0 | 1 | 0.200 | | 0 | 1 | 0 | 0.000 | | 0 | 1 | 1 | 0.150 | | 1 | 0 | 0 | 0.150 | | 1 | 0 | 1 | 0.120 | | 1 | 1 | 0 | 0.100 | | 1 | 1 | 1 | 0.180 | Calculate the following probabilities: (a) \( P(X_0 = 1, X_1 = 0, X_2 = 1) \) (b) \( P(X_0 = 0, X_1 = 1) \) (c) \( P(X_0 = 1) \) (d) \( P(X_1 = 0 \mid X_0 = 1) \) (e) \( P(X_1 = 0, X_2 = 1 \mid X_0 = 1) \) (f) \( P(X_1 = 0 \mid X_0 = 1, X_2 = 1) \) # Independence In the joint distribution from the previous problem, is \(X_0\) independent of \(X_1\)? Justify your answer.
Expert Solution
Step 1

a)

PX0=1,X1=0,X2=1=0.120, from the given table

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