1. Make a word situation problem that involves both rules of Rule of Sums and Product 2. Illustrate or draw the solution that is needed to answer the problem. 3. MUST BE ORIGINAL OR UNIQUE THAT IS NEVER SEEN ON THE INTERNET OR GOOGLE. 4. It should be NOT REPHRASE. Example of what I am talking about: A word problem that would involve both rules of FCP (Rule of Sums and Product) Raj wants to go to Delhi. He can choose from 33 bus services or 22 train services to head from home to downtown Mumbai. From there, he can choose from 22 bus services or 33 train services to head to Delhi. Now, he has to purchase a bus concession ( which will only allow him to take buses) or a train concession ( which will only allow him to take trains). If he has money for only one of these concession, how many ways he can go to Delhi? Step 2 Solution: If Raj purchases a bus concession, number of ways he has=3×2=6=3×2=6 (Rule of product) If Raj purchases a train concession, number of ways he has=2×3=6=2×3=6 (Rule of product) Total number of ways=6+6=12=6+6=12 (Rule of sum)
1. Make a word situation problem that involves both rules of Rule of Sums and Product
2. Illustrate or draw the solution that is needed to answer the problem.
3. MUST BE ORIGINAL OR UNIQUE THAT IS NEVER SEEN ON THE INTERNET OR GOOGLE.
4. It should be NOT REPHRASE.
Example of what I am talking about:
A word problem that would involve both rules of FCP (Rule of Sums and Product)
Raj wants to go to Delhi. He can choose from 33 bus services or 22 train services to head from home to downtown Mumbai. From there, he can choose from 22 bus services or 33 train services to head to Delhi. Now, he has to purchase a bus concession ( which will only allow him to take buses) or a train concession ( which will only allow him to take trains). If he has money for only one of these concession, how many ways he can go to Delhi?
Solution:
If Raj purchases a bus concession, number of ways he has=3×2=6=3×2=6 (Rule of product)
If Raj purchases a train concession, number of ways he has=2×3=6=2×3=6 (Rule of product)
Total number of ways=6+6=12=6+6=12 (Rule of sum)
Step by step
Solved in 2 steps with 1 images
