1. List any discontinuities in the following graphs (if there is an oblique asymptote just state YES OR NO cxists) 3x +5 3x2 -4 x2 - x f(x) : x - 2 f(x) = f(x) = f(x) %3D %3D %3D Discontinuity 2-5x x-2 X-1 Vertical Asymptote Horizontal Asymptote Oblique Asymptote Hole
![1. List any discontinuities in the following graphs (if there is an oblique asymptote just state YES OR NO
cxists)
x2-
f(x) =
3x +5
3x2 - 4
Discontinuity
f(x)
f(x) =
f(x) =
%3D
%3D
x-2
2-5x
X-2
X-1
Vertical Asymptote
Horizontal
Asymptote
Oblique Asymptote
Hole](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F791aaf86-9b97-499a-b345-526a9474723a%2F3ef1b2c4-f8e5-4fd7-9c0d-8d47168452d4%2Ftb4il4m_processed.jpeg&w=3840&q=75)
![](/static/compass_v2/shared-icons/check-mark.png)
A function is said to have a discontinuity at a point then the function is not defined at that point.
A function is said to have a vertical asymptote at a point L if the function's value is infinity at that point. Or we can say a function has a vertical asymptote at a point if the denominator is equal to 0 at that point.
A function is said to have a horizontal asymptote at a point L if
A function has an oblique asymptote if the degree of the numerator is 1 more than that of the denominator.
A function has a hole at a point if the numerator and denominator after factoring have a common term. We then have to put that common term equal to 0 and get the value of x and then simplify the function and put the value of x obtained to get the value of y .
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