1. Let f(x)=x-4x+6x³- - - 5a2+3 1. If you think carefully about your process, the answers to parts (b) and (c) should not be very difficult to determine once you have found the answer to part (a). dy (e) Find T3(x) for f(x) based at b= 1. You do not need to expand your answer. Note: This gives a method for writing a polynomial in powers of (x-1) instead of powers of x. It is sometimes useful if you are interested in the values of the polynomial near = 1. Another technique would be to substitute u = ru+1, multiply out the polynomial, collect together powers of u and then substitute back u=x-1. Using Taylor polynomials is a bit easier. 1 or
1. Let f(x)=x-4x+6x³- - - 5a2+3 1. If you think carefully about your process, the answers to parts (b) and (c) should not be very difficult to determine once you have found the answer to part (a). dy (e) Find T3(x) for f(x) based at b= 1. You do not need to expand your answer. Note: This gives a method for writing a polynomial in powers of (x-1) instead of powers of x. It is sometimes useful if you are interested in the values of the polynomial near = 1. Another technique would be to substitute u = ru+1, multiply out the polynomial, collect together powers of u and then substitute back u=x-1. Using Taylor polynomials is a bit easier. 1 or
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Transcribed Image Text:1. Let f(x)=x-4x+6x³-
-
-
5a2+3 1. If you think carefully about your process,
the answers to parts (b) and (c) should not be very difficult to determine once you have
found the answer to part (a).
dy
(e) Find T3(x) for f(x) based at b= 1. You do not need to expand your answer.
Note: This gives a method for writing a polynomial in powers of (x-1) instead
of powers of x. It is sometimes useful if you are interested in the values of the
polynomial near = 1. Another technique would be to substitute u =
ru+1, multiply out the polynomial, collect together powers of u and then
substitute back u=x-1. Using Taylor polynomials is a bit easier.
1 or
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