1. Let F be a nonempty family of transitive relations. Prove that NF is a transitive relation. Hint. This requires two parts to be settled in the proof.

Advanced Engineering Mathematics
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ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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1.
Let F be a nonempty family of transitive relations. Prove
that NF is a transitive relation.
Hint. This requires two parts to be settled in the proof.
2.
Let A Ø be a set. Prove that A? is an equivalence relation
on A.
3.
Prove that if a reflexive R (on some set A) satisfies
x Ry A xRz yRz
(1)
for all x, y, z, then it is an equivalence relation.
Caution. Note the order of the x, y, z in (1)!
4.
Show that if for a relation R
we know that R2 C R, then R
is transitive, and conversely.
Hint. There are two directions in the sought proof.
5.
Without using the U R representation of R*,
Prove that for any set relation R (we did not pick it to be "on" any
particular set)
R* = N{e:RCQA Q is transitive}
Hint. You may use Questions 1 and 2 above even if you did not prove
them.
| Give an example of two equivalence relations R and S on
the set A = {1, 2, 3} such that RUS is not an equivalence relation.
6.
%3D
Transcribed Image Text:1. Let F be a nonempty family of transitive relations. Prove that NF is a transitive relation. Hint. This requires two parts to be settled in the proof. 2. Let A Ø be a set. Prove that A? is an equivalence relation on A. 3. Prove that if a reflexive R (on some set A) satisfies x Ry A xRz yRz (1) for all x, y, z, then it is an equivalence relation. Caution. Note the order of the x, y, z in (1)! 4. Show that if for a relation R we know that R2 C R, then R is transitive, and conversely. Hint. There are two directions in the sought proof. 5. Without using the U R representation of R*, Prove that for any set relation R (we did not pick it to be "on" any particular set) R* = N{e:RCQA Q is transitive} Hint. You may use Questions 1 and 2 above even if you did not prove them. | Give an example of two equivalence relations R and S on the set A = {1, 2, 3} such that RUS is not an equivalence relation. 6. %3D
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