1. Knight P11.74 Given the equation of position versus time, x(t) = Ae-t cos(wt + o) Show that the time derivatives of this equation are: dx dt d²x dt2 - Aße-t cos(wt + o) - Awe-t sin(wt + o) =(A3² - Aw²) e-t cos(wt + 0) +2Aßwe-t sin(wt + o)
1. Knight P11.74 Given the equation of position versus time, x(t) = Ae-t cos(wt + o) Show that the time derivatives of this equation are: dx dt d²x dt2 - Aße-t cos(wt + o) - Awe-t sin(wt + o) =(A3² - Aw²) e-t cos(wt + 0) +2Aßwe-t sin(wt + o)
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Transcribed Image Text:Questions
In the following three exercises you will solve the
Newton's second law equation for a horizontal
oscillating spring with spring constant, k, and linear
drag coefficient, b.
1. Knight P11.74 Given the equation of position
versus time,
2
x(t) = Ae-t cos(wt + o)
Show that the time derivatives of this equation are:
dx Aße-t cos(wt + o)
dt
==
d²x
dt²
- Awe-Bt
=(A3² - Aw²) e-Bt cos(wt + po)
+2Aßwe-t sin(wt + o)
t sin(wt + o)
Substitute your answer from Q1 into the

Transcribed Image Text:Useful information
Product rule
Trig derivatives
d(uv) = du v + u dv
d
du
d
du
cos au = -a sin au
sin au= a cos au
Derivative of natural log base
d
- eau = aeau
du
Sine plus cosine equation: if the sum of sines and co-
is zero for all angles, then the coefficients of the sine
and cosines are themselves identically zero
0= P cos u + Q sin u
P = 0
Q=0
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