1. Ken, a motorcyclist heading east through a small town Antipolo accelerates as he passes the signpost marking the city limits. His acceleration is constant, a=4.0 m/s². At t=0,he is 5.0 m east of the signpost and has a velocity of 3.0 m/s. Find: a) His position and velocity at t=2s (using eq. 5 and eq. 3) b) His position at v-5 m/s (using eq. 5)
1. Ken, a motorcyclist heading east through a small town Antipolo accelerates as he passes the signpost marking the city limits. His acceleration is constant, a=4.0 m/s². At t=0,he is 5.0 m east of the signpost and has a velocity of 3.0 m/s. Find: a) His position and velocity at t=2s (using eq. 5 and eq. 3) b) His position at v-5 m/s (using eq. 5)
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REFER TO THE FORMULA GIVEN. USE IT TO SOLVE THE PROBLEM.
![SOLVE THE FOLLOWING PROBLEM AND SHOW YOUR COMPLETE SOLUTIONS. EXPLAIN YOUR ANSWER
FOR BETTER UNDERSTANDING. IF APPLICABLE ILLUSTRATE A FREE BODY DIAGRAM.
1. Ken, a motorcyclist heading east through a
small town Antipolo accelerates as he passes
the signpost marking the city limits. His
acceleration is constant, a=4.0 m/s². At t=0, he
is 5.0 m east of the signpost and has a velocity
of 3.0 m/s. Find:
a) His position and velocity at t=2s (using eq. 5
and eq. 3)
b) His position at v=5 m/s (using eq.5)
Equation 3
Equation 4
Equation 5
RECTILINEAR MOTION
V₁= V₁ + at
V₁² = V² + 2nd or
V₁ = V² + 20(x₂-xa)
FREE FALL
V=V2+2gd or
v=V² - 2g(y-yo)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F511f63a1-ceef-4f7c-bc33-fe537568995a%2F06ec350c-c167-491d-a846-729edcec8805%2Fwa070fo_processed.jpeg&w=3840&q=75)
Transcribed Image Text:SOLVE THE FOLLOWING PROBLEM AND SHOW YOUR COMPLETE SOLUTIONS. EXPLAIN YOUR ANSWER
FOR BETTER UNDERSTANDING. IF APPLICABLE ILLUSTRATE A FREE BODY DIAGRAM.
1. Ken, a motorcyclist heading east through a
small town Antipolo accelerates as he passes
the signpost marking the city limits. His
acceleration is constant, a=4.0 m/s². At t=0, he
is 5.0 m east of the signpost and has a velocity
of 3.0 m/s. Find:
a) His position and velocity at t=2s (using eq. 5
and eq. 3)
b) His position at v=5 m/s (using eq.5)
Equation 3
Equation 4
Equation 5
RECTILINEAR MOTION
V₁= V₁ + at
V₁² = V² + 2nd or
V₁ = V² + 20(x₂-xa)
FREE FALL
V=V2+2gd or
v=V² - 2g(y-yo)
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