R49 k6 k+ Vs -E = 28 VE V, RRR 3 k10.4 kf212 kl12 kFigure 4.21II. A-to-Y ConversionA. Solve for the required values with complete solution and progressive simplified circuits.Box the final answer for the required values.1. In Fig. 4.22, use delta-wye transformations to calculate both Rr and IT with Vs =12 V and the following resistor values RẠ = 27 k, Rg = 33 k, Rp = 39 k, Rg =47 k, and Rc = 100 k.R.Figure 4.22 Chapter AssessmentsI Series-Parallel Circuit AnalysisA. Solve for the required values with complete solution and progressive simplified circuits.Box the final answer for the required values.1. In Fig. 4.19, solve for Ry, Ir, l2, I4, and PR, = 75 0R= 150 2V,- 12 VR-330 0R- 180 1Figure 4.192. For each of the circuits shown in Fig. 4.20,a. find the equivalent resistance seen by the source,b. find the power developed by the source.210 0280 N100120Ω180Ω:१15 0 90 V/40 Ω30 mA (200 225 0(a)(b)Figure 4.203. For the network in Fig. 4.21Note: E is also equivalent to the designation Vs or Vr for voltage source and Is isequivalent to lr for total current of the circuit being analyzed.a. Find currents Is, I2, and 16.b. Find voltages V1 and Vs.c. Find the power delivered to the 3 ka resistor.

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Answered: 1. In Fig. 4.19, solve for RT, IT, 12,…

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1. In Fig. 4.19, solve for RT, IT, 12, 14, and P₁ R₁-750 R₂ = 1500 www V, 12V R-3300 Figure 4.19 FL-180 (1

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Concept explainers

Graph theory

It is that part of network analysis where the configuration is called graph or structure of the network system when all of the elements (e.g., R, L, and C) in a network system are substituted with lines having circles/rings or dots across both endpoints. The study of the solution of the networks and circuits with the help of graphs is known as graph theory. The objective is to know the mathematics behind the network analysis.

Question

R4
9 k
6 k
+ Vs -
E = 28 VE V, R
R
R 3 k
10.4 kf2
12 kl
12 k
Figure 4.21
II. A-to-Y Conversion
A. Solve for the required values with complete solution and progressive simplified circuits.
Box the final answer for the required values.
1. In Fig. 4.22, use delta-wye transformations to calculate both Rr and IT with Vs =
12 V and the following resistor values RẠ = 27 k, Rg = 33 k, Rp = 39 k, Rg =
47 k, and Rc = 100 k.
R.
Figure 4.22

Chapter Assessments
I Series-Parallel Circuit Analysis
A. Solve for the required values with complete solution and progressive simplified circuits.
Box the final answer for the required values.
1. In Fig. 4.19, solve for Ry, Ir, l2, I4, and P
R, = 75 0
R= 150 2
V,- 12 V
R-330 0
R- 180 1
Figure 4.19
2. For each of the circuits shown in Fig. 4.20,
a. find the equivalent resistance seen by the source,
b. find the power developed by the source.
210 0
280 N
100
120Ω180Ω:
१15 0 90 V/
40 Ω
30 mA (
200 2
25 0
(a)
(b)
Figure 4.20
3. For the network in Fig. 4.21
Note: E is also equivalent to the designation Vs or Vr for voltage source and Is is
equivalent to lr for total current of the circuit being analyzed.
a. Find currents Is, I2, and 16.
b. Find voltages V1 and Vs.
c. Find the power delivered to the 3 ka resistor.

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