1. In a linear accelerator, protons are accelerated from rest through a potential difference to a speed of approximately 3.1 x 100 meters per second. The resulting proton beam produces a current of 2.0 x 10 ampere. v=i_mv² 29 betounib bir b. one Proton Beam Region of Field B a. Determine the potential difference through which the protons were accelerated. = 1/2mv² =qv 2 230 V = 1.67 X10-27 (3.1x106) ² ·x (Positive z out of page) 2(1.6x10-19) 5 0152. 188 V -19 OF 10 ni oran $300 (6 grysis w inigi (6) If the beam is stopped in a target, determine the amount of thermal energy that is produced in the target minute.
1. In a linear accelerator, protons are accelerated from rest through a potential difference to a speed of approximately 3.1 x 100 meters per second. The resulting proton beam produces a current of 2.0 x 10 ampere. v=i_mv² 29 betounib bir b. one Proton Beam Region of Field B a. Determine the potential difference through which the protons were accelerated. = 1/2mv² =qv 2 230 V = 1.67 X10-27 (3.1x106) ² ·x (Positive z out of page) 2(1.6x10-19) 5 0152. 188 V -19 OF 10 ni oran $300 (6 grysis w inigi (6) If the beam is stopped in a target, determine the amount of thermal energy that is produced in the target minute.
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how would you do part b? this is a non graded practice worksheet
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to a se
a speed of approximately
3.1 x 100 meters per second. The resulting proton beam produces a current of
2.0 x 10- ampere.
a.
// mv² =qv
b.
one
betounib bigh
v=1_mv²
29
Proton Beam
Region of
Field B
Determine the potential difference through which the protons were accelerated.
(Positive z
out of page)
2
12V=1-67x10-27 (3.1x10²) 50152.188 V
16
2(1.6x10-19)
-19 OF 10 ni ost
yards awod (0)
103000
Ingin (8) BJ (4)
If the beam is stopped in a target, determine the amount of thermal energy that is produced in the target in
minute.
Winstwo Jastando & ampo griw erT J dignol bns m 22sms earl gniw nir icinosisort A
asm si to obutingsm"
Transcribed Image Text:1. In a linear accelerator, protons are accelerated from rest through a potential difference to
to a se
a speed of approximately
3.1 x 100 meters per second. The resulting proton beam produces a current of
2.0 x 10- ampere.
a.
// mv² =qv
b.
one
betounib bigh
v=1_mv²
29
Proton Beam
Region of
Field B
Determine the potential difference through which the protons were accelerated.
(Positive z
out of page)
2
12V=1-67x10-27 (3.1x10²) 50152.188 V
16
2(1.6x10-19)
-19 OF 10 ni ost
yards awod (0)
103000
Ingin (8) BJ (4)
If the beam is stopped in a target, determine the amount of thermal energy that is produced in the target in
minute.
Winstwo Jastando & ampo griw erT J dignol bns m 22sms earl gniw nir icinosisort A
asm si to obutingsm
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