1. If you were constructing a 99% confidence interval of the population mean based on a sample of n = 25 where the standard deviation of the sample s = 0.05, the critical value of t will be: a. 2.4922 b. 2.4851 c. 2.7874 d. 2.3562 e. 2.7969 1. Researchers determine that 60 Kleenex tissues is the average number of tissues used during a cold. Suppose a random sample of 100 Kleenex users yielded the following statistics on the number of tissues used during a cold: x = 52 and s = 22. Using the sample information provided, the value of the test statistic is a. t = (52 - 60)/(22/1002) b. t = (52 - 60)/22 c. t = (52 - 60)/(22/102) d. t = (52 - 60)/(22/10) e. t = (52 - 60)/(22/100)
1. If you were constructing a 99% confidence interval of the population mean based on a sample of n = 25 where the standard deviation of the sample s = 0.05, the critical value of t will be: a. 2.4922 b. 2.4851 c. 2.7874 d. 2.3562 e. 2.7969 1. Researchers determine that 60 Kleenex tissues is the average number of tissues used during a cold. Suppose a random sample of 100 Kleenex users yielded the following statistics on the number of tissues used during a cold: x = 52 and s = 22. Using the sample information provided, the value of the test statistic is a. t = (52 - 60)/(22/1002) b. t = (52 - 60)/22 c. t = (52 - 60)/(22/102) d. t = (52 - 60)/(22/10) e. t = (52 - 60)/(22/100)
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
1. If you were constructing a 99% confidence interval of the population mean based on a sample of n = 25 where the standard deviation of the sample s = 0.05, the critical value of t will be:
| a. 2.4922 |
| b. 2.4851 |
| c. 2.7874 |
| d. 2.3562 |
| e. 2.7969 |
1. Researchers determine that 60 Kleenex tissues is the average number of tissues used during a cold. Suppose a random sample of 100 Kleenex users yielded the following statistics on the number of tissues used during a cold: x = 52 and s = 22. Using the sample information provided, the value of the test statistic is
| a. t = (52 - 60)/(22/1002) |
| b. t = (52 - 60)/22 |
| c. t = (52 - 60)/(22/102) |
| d. t = (52 - 60)/(22/10) |
| e. t = (52 - 60)/(22/100) |
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