1. How much alkalinity is consumed by a dose of 60 mg/L of ferric chloride? What is the equivalent alkalinity if reported in terms of CaCO3? and how much solids (precipitate) will be produced? (MWt of Fe2(SO4)3 = 400 mg/mmole, Fe(OH)3 = 106.9 mg/mmole, Ca(OH)2 = 74.1 mg/mmole, CaCO3 = 100.1 mg/mmole, Ca(HCO3)2 = 162.1 mg/mmole). The following stoichiometric reaction occurs: Fe₂(SO4)3 +3 Ca(OH)₂ → 2 Fe(OH)3 (s) + 3 Ca(SO4)3 a) 45.0 mg/L, 27.7 mg/L, 32.07 mg/L 24.3 mg/L, 45.0 mg/L, 23.7 mg/L 33.3 mg/L, 72.9 mg/L, 32.07 mg/L 33.3 mg/L, 45.0 mg/L, 32.07 mg/L
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Answer is D, wanting to know how to calculate.
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