1. Here is a program that simply reads characters from the keyboard until the user hits the enter (or return) key. Add code to the program so that it allows the user to enter up to a 32-bit integer in hexadecimal and converts the number to int format. Your algorithm should make use of the masking operation described above. The program should display the int in both hexadecimal and decimal format for the user. Assume that the user will not make mistakes. /* readHex.c Asks user to enter a number in hexadecimal. * INCOMPLETE PROGRAM FOR EXERCISE. * 2017-09-29: Bob Plantz */ #include #include int main(void) { int x; unsigned char aChar; printf("Enter an integer in hexadecimal: "); fflush(stdout); x = 0; read (STDIN_FILENO, &aChar, 1); while (aChar != '\n') { read (STDIN_FILENO, &aChar, 1); } // initialize result. // get first character // look for return key printf("You entered %#010x = %d (decimal)\n\n", x, x); return 0;

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
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1. Here is a program that simply reads characters from the keyboard until the
user hits the enter (or return) key. Add code to the program so that it allows the
user to enter up to a 32-bit integer in hexadecimal and converts the number to
int format. Your algorithm should make use of the masking operation
described above. The program should display the int in both hexadecimal
and decimal format for the user. Assume that the user will not make mistakes.
/* readHex.c
* Asks user to enter a number in hexadecimal.
* INCOMPLETE PROGRAM FOR EXERCISE.
* 2017-09-29: Bob Plantz
$/
#include <stdio.h>
#include <unistd.h>
int main(void)
{
int x;
unsigned char aChar;
printf("Enter an integer in hexadecimal: ");
fflush(stdout);
x = 0;
read (STDIN_FILENO, &aChar, 1);
while (aChar != '\n')
{
read (STDIN_FILENO, &aChar, 1);
}
// initialize result
// get first character.
// look for return key
printf("You entered %#010x = %d (decimal)\n\n", x, x);
return 0;
Transcribed Image Text:1. Here is a program that simply reads characters from the keyboard until the user hits the enter (or return) key. Add code to the program so that it allows the user to enter up to a 32-bit integer in hexadecimal and converts the number to int format. Your algorithm should make use of the masking operation described above. The program should display the int in both hexadecimal and decimal format for the user. Assume that the user will not make mistakes. /* readHex.c * Asks user to enter a number in hexadecimal. * INCOMPLETE PROGRAM FOR EXERCISE. * 2017-09-29: Bob Plantz $/ #include <stdio.h> #include <unistd.h> int main(void) { int x; unsigned char aChar; printf("Enter an integer in hexadecimal: "); fflush(stdout); x = 0; read (STDIN_FILENO, &aChar, 1); while (aChar != '\n') { read (STDIN_FILENO, &aChar, 1); } // initialize result // get first character. // look for return key printf("You entered %#010x = %d (decimal)\n\n", x, x); return 0;
Expert Solution
Step 1

Since the question does not specify the masking procedure, I converted the hexadecimal value to a decimal number using a standard technique. In case you have any questions, kindly comment. In the code, I have included the appropriate comments.

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