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1. H2 + AICIs AI HCI +] n you start with 205 g of aluminum and 75.6 g of HCI, how many grams of, H2 can be made? AI 3 mol H2 2 mol AI 26.989 =23.029 I mol HCI 36.469HCI bmolHC)i mol, 3 mol Ha,D sglta 07gHa 75.6 Hl x Ans 2.02a Ha 'H2 b) What is the limiting reagent? . Ans l Ans C) Suppose you only made 1.98 g of H2. What is your % yield? 2. Fe CS2 FezS3 ----> a) How many grams of iron can be made from 119 g of Fe2S3 and 12.7 g C? x55-859e-63 u mol Fe amol Fen S i mol fe Imel Fez33 107.019Fe253 I mol C u mol Fex 55.85ae - 78749 12-0lgC 3mol c Imol Fe 11ag Fes3X 12-73(x. Ans le3.91 Ans Feg sz b) What is the limiting reagent? c) If you produce 35.6 g of Fe, what is your % yield? Ans

1. H2 + AICIs AI HCI +] n you start with 205 g of aluminum and 75.6 g of HCI, how many grams of, H2 can be made? AI 3 mol H2 2 mol AI 26.989 =23.029 I mol HCI 36.469HCI bmolHC)i mol, 3 mol Ha,D sglta 07gHa 75.6 Hl x Ans 2.02a Ha 'H2 b) What is the limiting reagent? . Ans l Ans C) Suppose you only made 1.98 g of H2. What is your % yield? 2. Fe CS2 FezS3 ----> a) How many grams of iron can be made from 119 g of Fe2S3 and 12.7 g C? x55-859e-63 u mol Fe amol Fen S i mol fe Imel Fez33 107.019Fe253 I mol C u mol Fex 55.85ae - 78749 12-0lgC 3mol c Imol Fe 11ag Fes3X 12-73(x. Ans le3.91 Ans Feg sz b) What is the limiting reagent? c) If you produce 35.6 g of Fe, what is your % yield? Ans

Chemistry
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Can you solve section c of question 1 and section c of question 2 and explain your process as to how you got your answer?
John Ohene D3)222 Name Date Block Stoichiometry Worksheet 3 Show all work using dimensional analysis!!! 1. AICI3 HCI H2 + -> AI you start with 205 g of aluminum and 75 6 g of HCI. how many grams of, H2 can be made? 2 mol AI 2.07g H2 Ans 2.07aHa 26.989AI THJow1 =23.029 3 mol Ha,9 sagta I mol HCI 36.469HCI bmolHC)" I mol 75.6 Hl x H2 b) What is the limiting reagent? Ans Cl Ans C) Suppose you only made 1.98 g of H2. What is your % yield? 2. Fe CS2 Fe2S3 C 55-35gFe-63ag Fe a) How many grams of iron can be made from 119 g of Fe2S3 and 12.7 g C? u mol Fe 207.a19 Fe amol Fegs3 Imol CxH mol Fex 55.85aFe = 78749 Ans le3.9 Fes3x Imel Fe233 ) mol fe 12-736> I mol Fe 13-0lgC 3 molC Fegsz b) What is the limiting reagent? Ans c) If you produce 35.6 g of Fe, what is your % yield? Ans 3. CO2 H2O ----> C6H1206 O2 a) How many grams of sugar can be made from 50.0 g of CO2 and 50.0 g of water? Imol CoHA o mol CO, mol 50.0g(02 I mol CH12O =34.1 Ans 34.la CoH,aO6 12 b) What is the excess reagent? Ans c) How many grams of the excess reagent are leftover? (hint- you'll need to use stoichiometry to solve this!) 50.0gl0, Imol (0xlo mol H20 Ans29. umol co Mork Don
Transcribed Image Text:John Ohene D3)222 Name Date Block Stoichiometry Worksheet 3 Show all work using dimensional analysis!!! 1. AICI3 HCI H2 + -> AI you start with 205 g of aluminum and 75 6 g of HCI. how many grams of, H2 can be made? 2 mol AI 2.07g H2 Ans 2.07aHa 26.989AI THJow1 =23.029 3 mol Ha,9 sagta I mol HCI 36.469HCI bmolHC)" I mol 75.6 Hl x H2 b) What is the limiting reagent? Ans Cl Ans C) Suppose you only made 1.98 g of H2. What is your % yield? 2. Fe CS2 Fe2S3 C 55-35gFe-63ag Fe a) How many grams of iron can be made from 119 g of Fe2S3 and 12.7 g C? u mol Fe 207.a19 Fe amol Fegs3 Imol CxH mol Fex 55.85aFe = 78749 Ans le3.9 Fes3x Imel Fe233 ) mol fe 12-736> I mol Fe 13-0lgC 3 molC Fegsz b) What is the limiting reagent? Ans c) If you produce 35.6 g of Fe, what is your % yield? Ans 3. CO2 H2O ----> C6H1206 O2 a) How many grams of sugar can be made from 50.0 g of CO2 and 50.0 g of water? Imol CoHA o mol CO, mol 50.0g(02 I mol CH12O =34.1 Ans 34.la CoH,aO6 12 b) What is the excess reagent? Ans c) How many grams of the excess reagent are leftover? (hint- you'll need to use stoichiometry to solve this!) 50.0gl0, Imol (0xlo mol H20 Ans29. umol co Mork Don
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