1. Given z, = 5 cos 377 +i sin 37 and z2= 37 +i sin 2 find z,z2 where 0se< 2x. cos 2 2 37 +i sin 2 377 = TUI cOS- 2 222 = 2.5(cosT+i sin 7) O zzz = 10(cos T+i sin 7) zz, = 10(cos 377+i sin 37)

Calculus: Early Transcendentals
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Author:James Stewart
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Chapter1: Functions And Models
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Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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37
find z,z2 where 0se< 2x.
2
1.
377
+i sin
and z2
Given z, = 5 cos
+i sin
cos
2
377
+i sin
= TUI cOS-
2
2
122 = 2.5(cos T+i sin 7)
21Z2 = 10(cos 7+i sin 7)
222 = 10(cos 37+i sin 37)
2. Find the product of z = 9 cis 10° and z2 = 5 cis 3° where 0<e <360°.
2,22 = 14cis 13°
422 = 45 cis 13°
zz2 = 45cis 7°
2122 = 1.8cis7o
3.
Given z1 = 6(cos 45°+i sin 45°) and z2 = 2(cos 90°+i sin 90°), find
where 0<e < 360°.
z2
Z1
= 3(cos 45°+i sin 45°)
21 = 3(cos 315°+i sin 315°)
Z2
= 4 (cos 315°+i sin 315°)
22
21 = 12(cos135°+i sin 135°)
22
Transcribed Image Text:37 find z,z2 where 0se< 2x. 2 1. 377 +i sin and z2 Given z, = 5 cos +i sin cos 2 377 +i sin = TUI cOS- 2 2 122 = 2.5(cos T+i sin 7) 21Z2 = 10(cos 7+i sin 7) 222 = 10(cos 37+i sin 37) 2. Find the product of z = 9 cis 10° and z2 = 5 cis 3° where 0<e <360°. 2,22 = 14cis 13° 422 = 45 cis 13° zz2 = 45cis 7° 2122 = 1.8cis7o 3. Given z1 = 6(cos 45°+i sin 45°) and z2 = 2(cos 90°+i sin 90°), find where 0<e < 360°. z2 Z1 = 3(cos 45°+i sin 45°) 21 = 3(cos 315°+i sin 315°) Z2 = 4 (cos 315°+i sin 315°) 22 21 = 12(cos135°+i sin 135°) 22
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