1. Given w = x²y³z+x*yz³, x = cos(4t),y = sin(5t),z = In(t). Write the tree diagram for . Then, find. 2. Given z=ln(3x+2y), x=s•sin(t), y=t• cos(t). Find and . dw dw dt dt əz əz əs at

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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The image contains two examples of computing the rate of change of a function using the chain rule in multivariable calculus.

**Example 1:**

Given the function:
\[ w = x^3y^2 + x^4y^3z \]
- \( x = \cos(4t) \)
- \( y = \sin(5t) \)
- \( z = \ln(3t) \)

**Diagram:**
There is a tree diagram showing the dependencies:
- The top node is \( w \).
- The second layer has nodes for \( x \), \( y \), and \( z \).
- The third layer has a node for \( t \).

**Chain Rule Calculation:**
The derivative \( \frac{dw}{dt} \) is calculated using the partial derivatives and the derivatives of \( x \), \( y \), and \( z \) with respect to \( t \). Each term is expanded and simplified step by step.

**Example 2:**

Given the function:
\[ z = \ln(3x + 2y) \]
- \( x = s \cdot \sin(t) \)
- \( y = 4 \cdot \cos(t) \)

**Diagram:**
A similar dependency tree diagram shows:
- The top node is \( z \).
- The second layer has nodes for \( x \) and \( y \).
- The bottom layer has nodes for \( s \) and \( t \).

**Chain Rule Calculation:**
The derivative \( \frac{dz}{dt} \) is calculated, involving partial derivatives \( \frac{\partial z}{\partial x} \), \( \frac{\partial z}{\partial y} \), \( \frac{\partial x}{\partial t} \), \( \frac{\partial y}{\partial t} \). The expressions are expanded and simplified to give the final result.

**Visual elements highlighted:**
- Red for partial derivatives.
- Green background for the part of the diagram related to \( \frac{dz}{dt} \).

Each mathematical expression is expanded, showing detailed steps for educational purposes, illustrating how to apply the chain rule in complex scenarios involving multiple variables and paths of dependency.
Transcribed Image Text:The image contains two examples of computing the rate of change of a function using the chain rule in multivariable calculus. **Example 1:** Given the function: \[ w = x^3y^2 + x^4y^3z \] - \( x = \cos(4t) \) - \( y = \sin(5t) \) - \( z = \ln(3t) \) **Diagram:** There is a tree diagram showing the dependencies: - The top node is \( w \). - The second layer has nodes for \( x \), \( y \), and \( z \). - The third layer has a node for \( t \). **Chain Rule Calculation:** The derivative \( \frac{dw}{dt} \) is calculated using the partial derivatives and the derivatives of \( x \), \( y \), and \( z \) with respect to \( t \). Each term is expanded and simplified step by step. **Example 2:** Given the function: \[ z = \ln(3x + 2y) \] - \( x = s \cdot \sin(t) \) - \( y = 4 \cdot \cos(t) \) **Diagram:** A similar dependency tree diagram shows: - The top node is \( z \). - The second layer has nodes for \( x \) and \( y \). - The bottom layer has nodes for \( s \) and \( t \). **Chain Rule Calculation:** The derivative \( \frac{dz}{dt} \) is calculated, involving partial derivatives \( \frac{\partial z}{\partial x} \), \( \frac{\partial z}{\partial y} \), \( \frac{\partial x}{\partial t} \), \( \frac{\partial y}{\partial t} \). The expressions are expanded and simplified to give the final result. **Visual elements highlighted:** - Red for partial derivatives. - Green background for the part of the diagram related to \( \frac{dz}{dt} \). Each mathematical expression is expanded, showing detailed steps for educational purposes, illustrating how to apply the chain rule in complex scenarios involving multiple variables and paths of dependency.
1. **Given** \( w = x^2 y^3 z + x^4 y z^3 \), \( x = \cos(4t) \), \( y = \sin(5t) \), \( z = \ln(t) \). Write the tree diagram for \(\frac{dw}{dt}\). Then, find \(\frac{dw}{dt}\).

2. **Given** \( z = \ln(3x + 2y) \), \( x = s \cdot \sin(t) \), \( y = t \cdot \cos(t) \). Find \(\frac{\partial z}{\partial s}\) and \(\frac{\partial z}{\partial t}\).
Transcribed Image Text:1. **Given** \( w = x^2 y^3 z + x^4 y z^3 \), \( x = \cos(4t) \), \( y = \sin(5t) \), \( z = \ln(t) \). Write the tree diagram for \(\frac{dw}{dt}\). Then, find \(\frac{dw}{dt}\). 2. **Given** \( z = \ln(3x + 2y) \), \( x = s \cdot \sin(t) \), \( y = t \cdot \cos(t) \). Find \(\frac{\partial z}{\partial s}\) and \(\frac{\partial z}{\partial t}\).
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