1. Given the symmetrical components to be Vo 10/0° V, V₁ = 80/30° V, V₂ = 40/-30° V calculate the line-to-line voltages Vab, Vbc, and Vca. Vab = 120/60 A Vbc = 120/-60 Vca = 208/0 Vab = 120/30 (B) Vbc = 120 /-30 Vca = 208/180 Vab = 120/50 CVbc = 120/-50 Vca = 208/90 Vab = 120 /-60 (D) Vbc = 120 /60 Vca = 208 /-90
1. Given the symmetrical components to be Vo 10/0° V, V₁ = 80/30° V, V₂ = 40/-30° V calculate the line-to-line voltages Vab, Vbc, and Vca. Vab = 120/60 A Vbc = 120/-60 Vca = 208/0 Vab = 120/30 (B) Vbc = 120 /-30 Vca = 208/180 Vab = 120/50 CVbc = 120/-50 Vca = 208/90 Vab = 120 /-60 (D) Vbc = 120 /60 Vca = 208 /-90
Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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![1. Given the symmetrical components to be
Vo 10/0° V, V₁ = 80/30° V, V₂ = 40/-30° V
calculate the line-to-line voltages Vab, Vbc, and Vca.
Vab = 120/60
A
Vbc = 120/-60
Vca = 208/0
Vab = 120/30
(B) Vbc = 120 /-30
Vca = 208/180
Vab = 120/50
CVbc = 120/-50
Vca = 208/90
Vab = 120 /-60
(D) Vbc = 120 /60
Vca = 208 /-90](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8736ecf0-8256-4741-ab0e-ba16b9b6b2e7%2F3dd31f87-c4da-4ff8-936c-ed9da9f09660%2Fp41qs2_processed.jpeg&w=3840&q=75)
Transcribed Image Text:1. Given the symmetrical components to be
Vo 10/0° V, V₁ = 80/30° V, V₂ = 40/-30° V
calculate the line-to-line voltages Vab, Vbc, and Vca.
Vab = 120/60
A
Vbc = 120/-60
Vca = 208/0
Vab = 120/30
(B) Vbc = 120 /-30
Vca = 208/180
Vab = 120/50
CVbc = 120/-50
Vca = 208/90
Vab = 120 /-60
(D) Vbc = 120 /60
Vca = 208 /-90
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