1. Given the hit ratio of level-1 cache is 0.1 and the access time is 1, the hit ratio of level-2 cache is 0.2 and the access time is 10, the hit ratio of level-3 cache is 0.3 and the access time is 100, and the hit ratio of the main memory is 0.4 and the access time of the main memory is 1000, what are the CETA, NETA if 3-level cache is applied and the ETA if no cache is applied?

Q: Compute Average Memory Access Time (AMAT) for a system that consists of a 2- level cache design.…

A: Given:   L1 cache access time = 1 cycle L2 cache access time = 5 cycle memory access time = 20 cycle…

Q: Design a direct-mapped cache with 128 KB that uses 32-bits and 16 bytes per block. Calculate: -How…

A: Given:   Cache size = 128kb  Pysical address = 32-bits  Block Size = 16 bytes.

Q: Consider that we have a direct-mapped cache that uses 64-bit addresses. If each word/ block is 128…

A: We were given, that we have a direct-mapped cache that uses 64-bit addresses.Let's find out the…

Q: , define Tc= first-level cache access time= 0.2ns; Tm = memory access time= 0.8ns; H= first-level…

A: For a system with single level of cache, define Tc= first-level cache access time= 0.2ns; Tm =…

Q: Given: A MIPS computer system with 1 GB of main memory. It has a 4K-Byte direct-mapped cache with a…

A: Given: *) computer system with 1 GB of main memory  *) 4K-Byte direct-mapped cache . *) block size…

Q: a. Calculate the effective length of a memory cycle given a hit ratio of 0.9 and a clocking rate of…

A: Preconditions:  Clock cycle = (Processor frequency)-1                         = (1 / 16.67 ) * 10-6…

Q: alculate the hit time at L2 cache in a 1.3GHz. processor assuming that the global average memory…

A: Given Data : Frequency = 1.3 GHz Average memory access time =  5.81 cycles Hit rate at L1 =  0.91%…

Q: Clarify "unified cache" and "Hadley cache".

A: A cache is a memory unit with faster access than the main memory and is more significant than…

Q: Q2. A computer company finds that the average memory access time for its computers is 158 ns for…

A: INTRODUCTION: Memory is an electrical storage space that a computer uses to store data and…

Q: On the Motorola 68020 microprocessor, a cache access takes two clock cycles. Data access from main…

A: Solution:: a)  Preconditions:   One clock cycle = 60 ns   Given that,   Cache access takes two clock…

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Q: The terms "unified cache" and "Hadley cache" need to be clarified.

A: Cache is a memory unit that is larger than registers and provides faster access than main memory.…

Q: How many total bits are required for a direct-mapped cache with 256 KB of data and 8-word block…

A: We are going to solve this question by assuming that it is word addressable. The formula we were…

Q: A cache block has 64 kbyte. The main memory has latency 64 usec and bandwidth 1 GBps. What is the…

A: For a 1 GBps bandwidth, loading 109 bytes on line takes 1 second, so 64 bytes will take 64*1/109=64…

Q: Design and draw for each of the followings A- The cache organization B- The cache directory SET…

A: This type of mapping has an improved and  enhanced form of direct mapping which helps us to remove…

Q: 5. Your system has an 8-way set associative cache and addresses and data of length 16 bits. The…

A: Since it is given that set index bits are 9, we have Total sets = 29 = 512

Q: The terms "unified cache" and "Hadley cache" need to be clarified.

A: Unified cache : A unified cache is a cache that stores both data and code (instructions).  Figure…

Q: 4. Consider a 64K L2 memory and a 4K L1 4-way associative cache with block sizes of 512. a. How many…

A: Here we calculate the followings terms by using the given information and conclude the answer , so…

Q: Q3: find the cache memory organization under direct mapping for a system n has MM of 128 blocks, CM…

A: The reserve is separated into 16 arrangements of 4 lines each. Consequently,  4 pieces are expected…

Q: QUESTION 3 Construct an DFA over = (a, b,..... z), where any accepted string begins with least two…

A: To construct a DFA that accepts strings starting with at least two vowels and ending with at most…

Q: Design a 256KB direct-mapped data cache that uses a 32-bit address/data and 8 words per block.…

A: - We need to create a 256 kb direct-mapped data cache with the requirements and provide the bits for…

Q: Consider a computer with the following characteristics: total of 4 Mbyte of main memory; word size…

A: GIVEN THAT    Given that- Maximum memory size = 1 MB. Word size = 1 Byte. Block size = 16 bytes…

Q: 3. A direct-mapped cache is organized as with 512 sets and 4-byte blocks using a 24-bit address.…

A: Given:  4 byte blocks means block offset = log2(4)=2 512 sets means set offsets = log2(512)=9 Total…

Q: 6- In 8086Mp bus cycles, the signal (ALE) becomes '1' during clock cycle. 7- The type of the buffer…

A: As per our guidelines we are supposed to answer?️ only one question. Kindly repost other questions…

Q: The terms "unified cache" and "Hadley cache" need to be defined and explained in terms of what they…

A: To be determined: Explain the difference between a unified cache and a Harvard cache.

Q: For a processor with 32-bit bus width and address bus width, set-associative cache memory will be…

A: The correct answer is:-

Q: Give a brief summary of the cache protocol.

A: In multiprocessor systems, when many: Repositories share the same memory, it is possible for the…

Q: On the Motorola 68020 microprocessor, a cache access takes two clock cycles. Data access from main…

A: The Motorola 68020 is the 32 bit micro processor compatible with the earlier members  of the 680x0…

Q: Given that the main memory access time is 1200 ns and cache access time is 100 ns. The average…

A: Let the hit ratio be h, cache access time be C, and memory access time be M.We know that average…

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Q: On the Motorola 68020 microprocessor, a cache access takes two clock cycles. Data access from main…

A: step: 1 of 2 Preconditions: One clock cycle = 60 ns Given that, Cache access takes two clock cycles,…

Q: A certain two-way set-associative cache has an access time of 4 ns, compared to a miss time of 60…

A: The access time of a two-way set-associative cache is 4 nanoseconds, whereas the miss time is 60…

Q: Give a brief summary of the cache protocol

A: The answer of this question is as follows:

Q: On the Motorola 68020 microprocessor, a cache access takes two clock cycles. Data access from main…

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Q: The access time of cache is 100 us, the access time of main memory is 90 us, and hit ratio is 95%,…

A: Cache access time tc=100 Memory access time tm= 90 microsec. Hit ratio h=95%=0.95

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Q: s using write-thoug mits. The cache ope a read-hit ratio of system is such tha or read 70% of time…

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