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1. Given the differential equation y" +3y + 2y = Which of the %3D (1+e")' following equations result after the proposed particular solution is substituted into the given differential equation. 1 1+ex -2c,(x)e-2x - c,(x)e-*= 0 ex c;(x)e- c,(x)e¯* = 1+ ex 2x + %3D -2c (x)e-2x - c(x)e-*= 0 1 -2c,(x)e-2* - c,(x)e¬*= 1+ex 2x 1 -c,(x)e-2x – 2c,(x)e¯* = 1+ ex

1. Given the differential equation y" +3y + 2y = Which of the %3D (1+e")' following equations result after the proposed particular solution is substituted into the given differential equation. 1 1+ex -2c,(x)e-2x - c,(x)e-*= 0 ex c;(x)e- c,(x)e¯* = 1+ ex 2x + %3D -2c (x)e-2x - c(x)e-*= 0 1 -2c,(x)e-2* - c,(x)e¬*= 1+ex 2x 1 -c,(x)e-2x – 2c,(x)e¯* = 1+ ex

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Given the differential equation y" +3y + 2y = Which of the %3D (1+e") following equations result after the proposed particular solution is substituted into the given differential equation. -2x 1 %3D 1 + ex -2c,x)e-2x - c,(x)e-* 0 ex c;(x)e-2* + c¿(x)e¯* = 1 + ex %3D -2c,(x)e-2x - c,(x)e-X= 0 c;(x)e-2× + c,(x)e-* =0 1 -2c;(x)e¯2× – c;(x)e¬L | 1+ex o c;)e-2*+c;(x)e¯*= 0 -2x 1 1+ex
Transcribed Image Text:Given the differential equation y" +3y + 2y = Which of the %3D (1+e") following equations result after the proposed particular solution is substituted into the given differential equation. -2x 1 %3D 1 + ex -2c,x)e-2x - c,(x)e-* 0 ex c;(x)e-2* + c¿(x)e¯* = 1 + ex %3D -2c,(x)e-2x - c,(x)e-X= 0 c;(x)e-2× + c,(x)e-* =0 1 -2c;(x)e¯2× – c;(x)e¬L | 1+ex o c;)e-2*+c;(x)e¯*= 0 -2x 1 1+ex
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