please answer the following:1. Given that the electrochemical cell L gives a potential of 0.0570 V, determine the concentration of bromide ions present in its cathode half-cell.2. The equilibrium concentration of Pb2+ (aq) and [PbBr4]2- (aq) in the cathode half-cell of L are 0.15 M and 0.32 M, respectively. Determine the equilibrium constant for the formation of [PbBr4]2-.3. Write the overall redox reaction for the electrochemical cell H. Two chemists, Lee and Hee, are working on the electrochemistry of bromine species. They prepared thefollowing electrochemical cells (Table 1) at 298 K.Table 1. Two electrochemical cells to study the electrochemistry of bromine species.Cell L:Pt(s) | Br2(1) | Br¯(aq) (1.0 M) || Br¯(aq) (x M) from [PbBr4]¯| Br2(1) | Pt(s)Cell H:Pt(s) | Br21) | Br (aq) (x M) || BrO3 (aq) (0.43 M), H*(aq) (1.00 M) | Br2(1) | Pt(s)Lee prepared a concentration cell (L) where the cathode half-cell uses an equilibrium solution of [PbBr4] (aq)as the source of bromide ions. On the other hand, Hee prepared a galvanic cell (H), where the bromide ionconcentration in the anode is equal to that in the cathode of cell L.Given: E° red Br21/Br (aq) = +1.07 V

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please answer the following:

1. Given that the electrochemical cell L gives a potential of 0.0570 V, determine the concentration of bromide ions present in its cathode half-cell.

2. The equilibrium concentration of Pb2+ (aq) and [PbBr4]2- (aq) in the cathode half-cell of L are 0.15 M and 0.32 M, respectively. Determine the equilibrium constant for the formation of [PbBr4]2-.

3. Write the overall redox reaction for the electrochemical cell H.

Two chemists, Lee and Hee, are working on the electrochemistry of bromine species. They prepared the
following electrochemical cells (Table 1) at 298 K.
Table 1. Two electrochemical cells to study the electrochemistry of bromine species.
Cell L:
Pt(s) | Br2(1) | Br¯(aq) (1.0 M) || Br¯(aq) (x M) from [PbBr4]¯| Br2(1) | Pt(s)
Cell H:
Pt(s) | Br21) | Br (aq) (x M) || BrO3 (aq) (0.43 M), H*(aq) (1.00 M) | Br2(1) | Pt(s)
Lee prepared a concentration cell (L) where the cathode half-cell uses an equilibrium solution of [PbBr4] (aq)
as the source of bromide ions. On the other hand, Hee prepared a galvanic cell (H), where the bromide ion
concentration in the anode is equal to that in the cathode of cell L.
Given: E° red Br21/Br (aq) = +1.07 V

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