Answer #1 1. Given are the stations and elevations of a proposed symmetrical parabolic highway curve.POINTELEVATION (m)STATIONA6+0756+255 (PI)93.6090.0096.48C6+435Note: Lines AB and BC are the tangent lines of the proposed highway curve.The curve will clear a boulder at Sta. 6+276, and the elevation of the tip of the boulder is92.65m. Solve for the ff:a. length of the symmetrical curveb. stationing and elevation of PC2. Suppose that during the construction of the symmetrical curve in problem #1, it wasdscovered that left side of the grade intersection falls on a rocky terrain. To avoidadditional cost of excavation, the symmetrical curve is to be adjusted by adding a fill0.4174m high on the curve at its lowest point. If the location of the PT and the grades ofthe tangents remain the same, detemine the ff:a. Length of the new vertical parabolic curveb. Stationing and elevation of the new PCC. Stationing and elevation of lowest point of the new curve

Solution: As per the given table Considering the diagram Gradient of…

1. Given are the stations and elevations of a proposed symmetrical parabolic highwa STATION POINT A ELEVATION (m) 93.60 6+075 90.00 6+255 (PI) 6+435 C 96.48 Note: Lines AB and BC are the tangent lines of the proposed highway curve. The curve will clear a boulder at Sta, 6+276, and the elevation of the tip of the b

1. Given are the stations and elevations of a proposed symmetrical parabolic highwa STATION POINT A ELEVATION (m) 93.60 6+075 90.00 6+255 (PI) 6+435 C 96.48 Note: Lines AB and BC are the tangent lines of the proposed highway curve. The curve will clear a boulder at Sta, 6+276, and the elevation of the tip of the b

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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