1. For the circular foundation below, determine: a) the ultimate settlement and b) the settlement after 9 months, due to consolidation of the clay layer. Base your calculations on the values at the midpoint of the clay layer. F=200,000 lb 4 ft 6 ft 6 ft 14 ft 10 ft CLAY SAND W=5% = 32° G=2.65 eo= 0.4 eo= 0.9 C = 0.4 Y sat 115 pcf = 0.05 OCR =1.1 ROCK C, = 0.2 ft z/day Sult =D₁177 ft 59 months = D.109 ft

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Author:Braja M. Das
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Chapter8: Mat Foundations
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1. For the circular foundation below, determine: a) the ultimate settlement and b) the
settlement after 9 months, due to consolidation of the clay layer. Base your calculations on the
values at the midpoint of the clay layer.
F=200,000 lb
4 ft
6 ft
6 ft
14 ft
All
10 ft
CLAY
SAND
w=5%
= 32°
G = 2.65
eo= 0.4
eo= 0.9
C=0.4
Y sat 115 pcf C = 0.05
OCR=1.1
C = 0.2 ft 2/day
Sult = 0,177 ft
59 months = 0.109,
ROCK
2.
Assume that the footing in problem 1 is of a 6 ft radius. Calculate the ultimate bearing
capacity for the assumptions of general and local shear failures.
2
GENERAL gult = 33,834 Lofft ²
gult = 4,744 Ubift?
2
LOCAL
Transcribed Image Text:1. For the circular foundation below, determine: a) the ultimate settlement and b) the settlement after 9 months, due to consolidation of the clay layer. Base your calculations on the values at the midpoint of the clay layer. F=200,000 lb 4 ft 6 ft 6 ft 14 ft All 10 ft CLAY SAND w=5% = 32° G = 2.65 eo= 0.4 eo= 0.9 C=0.4 Y sat 115 pcf C = 0.05 OCR=1.1 C = 0.2 ft 2/day Sult = 0,177 ft 59 months = 0.109, ROCK 2. Assume that the footing in problem 1 is of a 6 ft radius. Calculate the ultimate bearing capacity for the assumptions of general and local shear failures. 2 GENERAL gult = 33,834 Lofft ² gult = 4,744 Ubift? 2 LOCAL
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for the pre consoldiation why did you muliply it by 1.025? can you explain where you got this number

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