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1. For a soap bubble, the inside pressure must be greater than that outside, and the surface tension acts like a skin to support this pressure difference Ap. The pressure difference is then a function of surface tension σ and bubble radius R, i.e., Ap = f(o, R). Using Buckingham Pi theorem, find the II group(s) associated with this problem and express them in the form II₁ = (II2, ..., II-r). (Ans: ApR = constant) σ

1. For a soap bubble, the inside pressure must be greater than that outside, and the surface tension acts like a skin to support this pressure difference Ap. The pressure difference is then a function of surface tension σ and bubble radius R, i.e., Ap = f(o, R). Using Buckingham Pi theorem, find the II group(s) associated with this problem and express them in the form II₁ = (II2, ..., II-r). (Ans: ApR = constant) σ

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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1. For a soap bubble, the inside pressure must be greater than that outside, and the surface tension acts like a skin to support this pressure difference Ap. The pressure difference is then a function of surface tension σ and bubble radius R, i.e., Ap = f(o, R). Using Buckingham Pi theorem, find the II group(s) associated with this problem and express them in the form II₁ = (II2, ..., II-r). (Ans: ApR = constant) σ
Transcribed Image Text:1. For a soap bubble, the inside pressure must be greater than that outside, and the surface tension acts like a skin to support this pressure difference Ap. The pressure difference is then a function of surface tension σ and bubble radius R, i.e., Ap = f(o, R). Using Buckingham Pi theorem, find the II group(s) associated with this problem and express them in the form II₁ = (II2, ..., II-r). (Ans: ApR = constant) σ
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