1. For a short period of time, the frictional driving force acting on the wheels of the 2200-kg van is FD = (600t2) N, where t is in seconds. If the van has a speed of 25 km/h when t = 0, determine its speed whent 5 s. %3D
1. For a short period of time, the frictional driving force acting on the wheels of the 2200-kg van is FD = (600t2) N, where t is in seconds. If the van has a speed of 25 km/h when t = 0, determine its speed whent 5 s. %3D
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![1. For a short period of time, the frictional driving force acting on the wheels of the 2200-kg van is
Fp = (600t2) N, where t is in seconds. If the van has a speed of 25 km/h when t = 0, determine
its speed whent = 5 s.
FD](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ffbae19ae-fe97-42ad-a9d0-6a05eafe9580%2F7d4020c4-ae9c-456d-b518-016d16b92a31%2Fkgd8698_processed.jpeg&w=3840&q=75)
Transcribed Image Text:1. For a short period of time, the frictional driving force acting on the wheels of the 2200-kg van is
Fp = (600t2) N, where t is in seconds. If the van has a speed of 25 km/h when t = 0, determine
its speed whent = 5 s.
FD
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