1. FizzBuzz 2.0 by CodeChum Admin Remember the game of FizzBuzz from the last time? Well, I thought of some changes in the game, and also with the help of loops as well. Firstly, you'll be asking for a random integer and then loop from 1 until that integer. Then, Implement these conditions in the game: • print "Fizz" if the number is divisible by • print "Buzz" if the number is divisible by • print "Fizzbuzz" if the number is divisible by both 3 and 5 • print the number itself if none of the above conditions are met

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
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Chapter1: Introduction
Section: Chapter Questions
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Program C

 

main.c
Test Cases
Executions
1. FizzBuzz 2.0
Fincludecstdie.h
nainO
int n:
by CodeChum Admin
main.c:20:5: error: 'else' without a previous 1f
20 |
else if("nS--e");
Remember the game of FizzBuzz from the last
time? Well, I thought of some changes in the
game, and also with the help of loops as well.
Firstly, you'll be asking for a random integer
and then loop from 1 until that integer. Then,
printf("Enter n: );
scanf("Xd,&n");
int ni - 0:
Expected Output
implement these conditions in the game:
while (nenn1):{
• print "Fizz" if the number is divisible by
Enter n: 15
if (A33-0 nXS-0);
{
11
12
• print "Buzz" if the number is divisible by
13
printf("fizzbuzz");
Fizz
14
• print "FizzBuzz" if the number is
15
divisible by both 3 and 5
16
else if("n3-0");
Buzz
• print the number itself if none of the
17
Fizz
printf("fizz");
above conditions are met
18
19
20
Fizz
21
else if("AS-0");
Input
Buzz
22
11
1. An integer
23
printf(buzz");
24
13
25
Output
26
14
27
FizzBuzz
The first line will contain a message prompt to
28
input the integer.
The succeeding lines will contain either a string
or an integer.
O Test Case 2
Enter n: 15
1
2
O Test Case 3
Fiz
4
Buzz
Fiz
Buzz
Transcribed Image Text:main.c Test Cases Executions 1. FizzBuzz 2.0 Fincludecstdie.h nainO int n: by CodeChum Admin main.c:20:5: error: 'else' without a previous 1f 20 | else if("nS--e"); Remember the game of FizzBuzz from the last time? Well, I thought of some changes in the game, and also with the help of loops as well. Firstly, you'll be asking for a random integer and then loop from 1 until that integer. Then, printf("Enter n: ); scanf("Xd,&n"); int ni - 0: Expected Output implement these conditions in the game: while (nenn1):{ • print "Fizz" if the number is divisible by Enter n: 15 if (A33-0 nXS-0); { 11 12 • print "Buzz" if the number is divisible by 13 printf("fizzbuzz"); Fizz 14 • print "FizzBuzz" if the number is 15 divisible by both 3 and 5 16 else if("n3-0"); Buzz • print the number itself if none of the 17 Fizz printf("fizz"); above conditions are met 18 19 20 Fizz 21 else if("AS-0"); Input Buzz 22 11 1. An integer 23 printf(buzz"); 24 13 25 Output 26 14 27 FizzBuzz The first line will contain a message prompt to 28 input the integer. The succeeding lines will contain either a string or an integer. O Test Case 2 Enter n: 15 1 2 O Test Case 3 Fiz 4 Buzz Fiz Buzz
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