PlsHelp ASAPProgram C main.cTest CasesExecutions1. FizzBuzz 2.0Fincludecstdie.hnainOint n:by CodeChum Adminmain.c:20:5: error: 'else' without a previous 1f20 |else if("nS--e");Remember the game of FizzBuzz from the lasttime? Well, I thought of some changes in thegame, and also with the help of loops as well.Firstly, you'll be asking for a random integerand then loop from 1 until that integer. Then,printf("Enter n: );scanf("Xd,&n");int ni - 0:Expected Outputimplement these conditions in the game:while (nenn1):{• print "Fizz" if the number is divisible byEnter n: 15if (A33-0 nXS-0);{1112• print "Buzz" if the number is divisible by13printf("fizzbuzz");Fizz14• print "FizzBuzz" if the number is15divisible by both 3 and 516else if("n3-0");Buzz• print the number itself if none of the17Fizzprintf("fizz");above conditions are met181920Fizz21else if("AS-0");InputBuzz22111. An integer23printf(buzz");241325Output261427FizzBuzzThe first line will contain a message prompt to28input the integer.The succeeding lines will contain either a stringor an integer.O Test Case 2Enter n: 1512O Test Case 3Fiz4BuzzFizBuzz

Use a for loop to iterate from 1 to given number n and then check for each of the number in which…

1. FizzBuzz 2.0 by CodeChum Admin Remember the game of FizzBuzz from the last time? Well, I thought of some changes in the game, and also with the help of loops as well. Firstly, you'll be asking for a random integer and then loop from 1 until that integer. Then, Implement these conditions in the game: • print "Fizz" if the number is divisible by • print "Buzz" if the number is divisible by • print "Fizzbuzz" if the number is divisible by both 3 and 5 • print the number itself if none of the above conditions are met

1. FizzBuzz 2.0 by CodeChum Admin Remember the game of FizzBuzz from the last time? Well, I thought of some changes in the game, and also with the help of loops as well. Firstly, you'll be asking for a random integer and then loop from 1 until that integer. Then, Implement these conditions in the game: • print "Fizz" if the number is divisible by • print "Buzz" if the number is divisible by • print "Fizzbuzz" if the number is divisible by both 3 and 5 • print the number itself if none of the above conditions are met

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Question

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PlsHelp ASAP

Program C

main.c
Test Cases
Executions
1. FizzBuzz 2.0
Fincludecstdie.h
nainO
int n:
by CodeChum Admin
main.c:20:5: error: 'else' without a previous 1f
20 |
else if("nS--e");
Remember the game of FizzBuzz from the last
time? Well, I thought of some changes in the
game, and also with the help of loops as well.
Firstly, you'll be asking for a random integer
and then loop from 1 until that integer. Then,
printf("Enter n: );
scanf("Xd,&n");
int ni - 0:
Expected Output
implement these conditions in the game:
while (nenn1):{
• print "Fizz" if the number is divisible by
Enter n: 15
if (A33-0 nXS-0);
{
11
12
• print "Buzz" if the number is divisible by
13
printf("fizzbuzz");
Fizz
14
• print "FizzBuzz" if the number is
15
divisible by both 3 and 5
16
else if("n3-0");
Buzz
• print the number itself if none of the
17
Fizz
printf("fizz");
above conditions are met
18
19
20
Fizz
21
else if("AS-0");
Input
Buzz
22
11
1. An integer
23
printf(buzz");
24
13
25
Output
26
14
27
FizzBuzz
The first line will contain a message prompt to
28
input the integer.
The succeeding lines will contain either a string
or an integer.
O Test Case 2
Enter n: 15
1
2
O Test Case 3
Fiz
4
Buzz
Fiz
Buzz

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