1. First solve Ax=v0t+1/2 at 2 to find the constant speed of the ball on the flat table. (x-direction) Speed from start to end on table is .64 seconds Distance of table is 1 meter Acceleration is 0 2. Then solve Ax=v0t+1/2 at 2 to find the time it takes for the ball to fall to the top of the coffee can. (y-direction) Height from table to top of can is .77 Velocity is 0 3. Then solve Ax=v0t+ 1/2 at 2 to find the distance the ball travels in the x-direction to the coffee can. (x-direction)
1. First solve Ax=v0t+1/2 at 2 to find the constant speed of the ball on the flat table. (x-direction) Speed from start to end on table is .64 seconds Distance of table is 1 meter Acceleration is 0 2. Then solve Ax=v0t+1/2 at 2 to find the time it takes for the ball to fall to the top of the coffee can. (y-direction) Height from table to top of can is .77 Velocity is 0 3. Then solve Ax=v0t+ 1/2 at 2 to find the distance the ball travels in the x-direction to the coffee can. (x-direction)
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![### Ball Motion Analysis:
In this activity, we will analyze the motion of a ball moving on a flat table and then falling off to the top of a coffee can. The purpose is to solve for the constant speed of the ball, the time it takes to fall, and the distance traveled in the x-direction.
#### Steps and Equations:
1. **Finding the Constant Speed of the Ball on the Flat Table (x-direction):**
Use the equation:
\[\Delta x = v_0 t + \frac{1}{2} a t^2\]
Given:
- Speed from start to end on the table: 0.64 seconds
- Distance of table: 1 meter
- Acceleration (a): 0 (since speed is constant)
By plugging in the values:
\[1 = v_0 \cdot 0.64 + \frac{1}{2} \cdot 0 \cdot (0.64)^2\]
Solve for \(v_0\).
2. **Finding the Time it Takes for the Ball to Fall to the Top of the Coffee Can (y-direction):**
Use the same equation:
\[\Delta y = v_0 t + \frac{1}{2} a t^2\]
Given:
- Height from table to top of can: 0.77 meters
- Initial velocity (v_0): 0 (since the ball starts from rest in the y-direction)
- Acceleration (a_g): 9.8 m/s² (gravitational acceleration)
By plugging in the values:
\[0.77 = 0 \cdot t + \frac{1}{2} \cdot 9.8 \cdot t^2\]
Solve for \(t\).
3. **Finding the Distance the Ball Travels in the x-direction to the Coffee Can (x-direction):**
Use the same equation:
\[\Delta x = v_0 t + \frac{1}{2} a t^2\]
Given:
- Initial velocity (v_0) from step 1
- Time (t) from step 2
- Acceleration (a): 0 (constant speed in the x-direction)
By plugging in the values from the](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fbca33481-84f0-4d0e-9458-2fdcb949c0ec%2Fe9b5cf9e-b935-41d1-8095-26876a74eb4e%2Fy00if3_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Ball Motion Analysis:
In this activity, we will analyze the motion of a ball moving on a flat table and then falling off to the top of a coffee can. The purpose is to solve for the constant speed of the ball, the time it takes to fall, and the distance traveled in the x-direction.
#### Steps and Equations:
1. **Finding the Constant Speed of the Ball on the Flat Table (x-direction):**
Use the equation:
\[\Delta x = v_0 t + \frac{1}{2} a t^2\]
Given:
- Speed from start to end on the table: 0.64 seconds
- Distance of table: 1 meter
- Acceleration (a): 0 (since speed is constant)
By plugging in the values:
\[1 = v_0 \cdot 0.64 + \frac{1}{2} \cdot 0 \cdot (0.64)^2\]
Solve for \(v_0\).
2. **Finding the Time it Takes for the Ball to Fall to the Top of the Coffee Can (y-direction):**
Use the same equation:
\[\Delta y = v_0 t + \frac{1}{2} a t^2\]
Given:
- Height from table to top of can: 0.77 meters
- Initial velocity (v_0): 0 (since the ball starts from rest in the y-direction)
- Acceleration (a_g): 9.8 m/s² (gravitational acceleration)
By plugging in the values:
\[0.77 = 0 \cdot t + \frac{1}{2} \cdot 9.8 \cdot t^2\]
Solve for \(t\).
3. **Finding the Distance the Ball Travels in the x-direction to the Coffee Can (x-direction):**
Use the same equation:
\[\Delta x = v_0 t + \frac{1}{2} a t^2\]
Given:
- Initial velocity (v_0) from step 1
- Time (t) from step 2
- Acceleration (a): 0 (constant speed in the x-direction)
By plugging in the values from the
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