1. Find the value of Ip and V, in the circuits shown in Fig. 10-20. -10V +16V +10V +10V IG. Ip 10k Vol 2k 2k DA G. -10v. X2 $1.2k Ip: IL G. 10k 3k 10k 3.3k 2k -10V +12V (b) (c) (d)

Q1) asks to show that the d.c. bias current to the differential pairs is Iccs = 0.6 mA But you used iccs= 0.6 to answer the question. isnt the question asking you to prove that without using iccs= 0.6 it gives you to answer the question?

can sameone solve this thanks

MIDTERM QUIZ Solve the following problems. Show your solution and enclosed in a box all FINAL ANSWERS (Numerical Value). 1. Design the network that will maintain V at 12 V for a load current of 200 mA. That is determine Vz. R and R. If the maximum Zener power is 500 mW, what is the maximum Zener current? Rs 16 Vo Vz RL 2. Determine Voand Sketch output waveform for the clipper network shown.

I need the answer as soon as possible

Answer to your Best

A. If you have solved a multisource problem with the mesh current approach, explain how you can experimentally confirm that the theoretical mesh currents agree with the real currents in the circuit. B. Assuming tht the theoretical currento do not exactly agree with the measured currents, what are the most likely sources of errors?

VCIS for Vcc-Referenced Load - Examples LOAD Vcc RLOAD Problem E2 RB1 Design components R31, R82 and Rcs for load current of 0.5 mA and 10% of the supply voltage across Rcs Q1 R82 Rcs Determine the range of loads such that VCE > 0.8V b. R81, R82 Vc 1k Pot 12V

SHOW, THE CIRCUIT DLAGRAMS BELOW CAL CULATE? (A. ). RT (B) It (c)Pr IT A. 150V C 132 Z02 D * 122 E to (2.) LL

RI Rc Vcc g1601 R R2. RE Ry 0100555-9870479447 VE CE g1601 The values of some resistors and source in the circuit are given below. g160100555 - 9870479447 16U g160100555- 987047944 Rg = 1k RI = 100k RC = 9k RE = g160100537047 According to what is given, For the transistor used in the circuit, hfe = hFE = 160100555-987047944/ = 10k VCC = 20V a0100555-987047944/ g160100555 - 987047944 a. | Find IC current • b. Find the value of the resistance = hoe = 0, VBE = g160100550687047944/ VCE = 10V and g1601005 87047944 g16010055 D. • to. What will happen if f. What will happen to Kv if Find the input resistance (ri). Find the voltage gain (Kv). R2. CE is removed? 0100555-9870479447 CE is removed? g160100555 - 987047944/ 141 g160100555- 987047944 141 704/ 7944