1. Find the value of Ip and V, in the circuits shown in Fig. 10-20.-10V+16V+10V+10VIG.Ip S,IpSSiE10k2k2kDIVelsi-10V$1.2kVezsisiIp2 |V.VeGeD210k3k$3.3k2k-10V+12V(a)(b)(c)(d)Fig. (10-20)

we know that current flow from higher potential to lower potential. a..>> The current will…

Answered: 1. Find the value of Ip and V, in the…

1. Find the value of Ip and V, in the circuits shown in Fig. 10-20. -10V +16V +10V +10V IG. Ip 10k Vol 2k 2k DA G. -10v. X2 $1.2k Ip: IL G. 10k 3k 10k 3.3k 2k -10V +12V (b) (c) (d)

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Concept explainers

Current Division Method

The generalized current divider formula is given by the following relation below,

Question

1. Find the value of Ip and V, in the circuits shown in Fig. 10-20.
-10V
+16V
+10V
+10V
IG.
Ip S,
IpS
Si
E10k
2k
2k
DI
Vel
si
-10V
$1.2k
Vez
si
si
Ip2 |
V.
Ve
Ge
D2
10k
3k
$3.3k
2k
-10V
+12V
(a)
(b)
(c)
(d)
Fig. (10-20)

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