#1. Show work please **Chapter 17: PHYS 203: Fundamentals of Physics****Basic Electricity****Key Concepts:**- **Electric charges and fields**- **Coulomb’s Law:** \[ F = \frac{kq_1q_2}{r^2} \]- **Simple DC circuits:** Series, Parallel, and Compound- **Ohm’s Law:** \[ V = IR \]- **Electrical Measurement****Reinforcement:**1. **Problem 1:** Find the value of charge of identical particles if the measured force of \( F = 0.300 \, \text{N} \) and the distance between them is 210 cm.2. **Problem 2:** An electric field is measured to exert a force of \( 2.21 \times 10^{-4} \, \text{N} \) on a particle with a charge of \( 4.55 \times 10^{-4} \, \text{C} \). What is the magnitude of that electric field?3. **Problem 3:** If a current drawn by a circuit with a resistance of \( 4.3 \, \text{k}\Omega \) doubles when you halve the cross-sectional area \( A = 0.2 \text{cm}^2 \) of a wire while keeping the length constant at 3.1 cm, what would the resistivity be?**Note:** This document focuses on fundamental concepts in electricity, providing key formulas and example problems to reinforce learning and application of physical principles in electrical contexts.

As per guidelines only first question is solved here. Given , Measured force , F = 300 N Distance between charge ,r = 210 cm = 2.1 m Charges are identical means q1 =q2 From coulomb's law , F = kq1q2r2 , where k = 9×109 N m2/C2q1 = q2 , so F = kq2r2= 300 N q = 300 N×(2.1m)29×109 N m2/C2 =3.83×10-4 C Charge on particle is 3.83×10-4 C

Answered: 1. Find the value of charge of…

Science

Physics

1. Find the value of charge of identical particles if the measured force of F = .300 N if and the distance betweell them is 210 cm.

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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