1. Find the unknown currents in the circuit shown in Figure 1.
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- What is CEMF?Question 15 In half wave rectifier with filter, if the capacitance is increased, the ripple factor increases. True False Moving to another question will save this response. ipa. If you do not go completely around the loop when applying Kirchhoff’s voltage law, then the algebraic sum of the voltages cannot be determined the algebraic sum of the voltages will always be positive the algebraic sum of the voltages will always be negative the algebraic sum is the voltage between the start and finish points b. A p -type semiconductor is a semiconductor doped with impurity atoms whose electron valence is +4 pentavalent impurity atoms trivalent impurity atoms
- A three-phase rectifier is supplied by a 173.2-V rms line-to-line 60-Hz source. The RL load is a 100 resistor in series with a 15-mH inductor. Determine THD taking Is1 = 1.350:- Consider the circuit in Figure a) What type of circuit is this? b) Find and Sketch the voltage waveform across RL, assume the diodes are practical. c) If 100uf capacitor parallel with the resistor, calculate the ripple is connected factor I O o Da. What is the effect of applying reverse voltage on a pn junction? b. What is the critical electric field and when will it happen?
- Q1-Determine the ripple factor (r) for the filtered rectifier with a load as indicated in the figure below.What are the main benefits of using the transformer in this circuit? * 1 :1 D, Vims =130v Vpi pri ) VpMsec) f= 50 HZ RL D4 100 uF D2 2kaDraw the input waveform and output waveform for the circuit given below with proper values marked in the figure. Assume D1 as germanium and D2 as silicon diodes. Input Vpp=20V, V1=5 v and V2=8 V. R DZ D1 Vin Vout V2 Maximum voltage of output waveform Minimum voltage of output waveform Windows huiPower supply circuit is delivering 0.5 A and an average voltage 20 V to the load as shown in the circuit below. The ripple voltage of the half wave rectifier is 0.5 V and the diode is represented using constant voltage model. The smoothing capacitor value is equal to 220V ams 5OHZ İL-DC =05A RL VL-DC =20V
- In half wave rectifier with filter, if the capacitance is increased, the ripple factor increases. True or false Q2: Draw the output waveform for the three shown circuits. 1- R1 +10V 10 kn D2 V 0- 5V 5 V -10V Diodes are IN914. 2- Assume Vm=20V, show the Vdc on the graph D2 3- Assume VM318V and V=5V. 34Power supply circuit is delivering 0.5 A and an average voltage 20 V to the load as shown in the circuit below. The ripple voltage of the half wave rectifier is 0.5 V and the diode is represented using constant voltage model. The smoothing capacitor value is equal to 220V rmsh soHz} VL-DC =20V 0.01 F 0.02 F 0.0167 F None of the above