1. Find the tangent vector to the curve 6t r(t) = [t³ – t, t+1 , (2t + 1)*] at t = 1.

Algebra and Trigonometry (6th Edition)
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ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Question (3):

1. Find the tangent vector to the curve
6t
r(t) = [t³ – t,;
(2t + 1)2]
t+
at t = 1.
2. Find the length of the curve r(t)
0<t< 2n.
e'i + e' sin 2tj + e' cos 2tk,
3. Find a vector function that satisfies the conditions
r"(t) = 12ti – 31-/2j+2k,
r'(1) = j, r(1) = 2i – k.
4. Using the chain rule, find the following
A. 4, if z = u*v?w² and u = t³, v = 3t – 6, and w = t² +1.
B. and , if z = (x² + y²)8/2, and r = e=" sin v, y = e=" cos v.
5. Let f(r, y) = ce" + cos(ry) and P : (2,0).
A. Find the directional derivative of f at P in the direction v = 31 – 4j.
B. Find the direction of maximum increase of f at the point P.
6. Let f(x, y, z) = e* cosh y + z and P : (-1,0,0). Find the derivative
of f at the point P in the direction of v = i+ 2j+2k.
7. If f is a scalar field and v = [v1, v2, v3] is a vector field, show that
div(fv) = fdiv(v) + v • V(f).
%3D
8. Find div(v), if v is given by
v = (r? + y? + 22)--1, -y, -2].
Transcribed Image Text:1. Find the tangent vector to the curve 6t r(t) = [t³ – t,; (2t + 1)2] t+ at t = 1. 2. Find the length of the curve r(t) 0<t< 2n. e'i + e' sin 2tj + e' cos 2tk, 3. Find a vector function that satisfies the conditions r"(t) = 12ti – 31-/2j+2k, r'(1) = j, r(1) = 2i – k. 4. Using the chain rule, find the following A. 4, if z = u*v?w² and u = t³, v = 3t – 6, and w = t² +1. B. and , if z = (x² + y²)8/2, and r = e=" sin v, y = e=" cos v. 5. Let f(r, y) = ce" + cos(ry) and P : (2,0). A. Find the directional derivative of f at P in the direction v = 31 – 4j. B. Find the direction of maximum increase of f at the point P. 6. Let f(x, y, z) = e* cosh y + z and P : (-1,0,0). Find the derivative of f at the point P in the direction of v = i+ 2j+2k. 7. If f is a scalar field and v = [v1, v2, v3] is a vector field, show that div(fv) = fdiv(v) + v • V(f). %3D 8. Find div(v), if v is given by v = (r? + y? + 22)--1, -y, -2].
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