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1. Find the settlements of the Mat Foundation and check angular rotation using Empirical Formula. Use any reasonable value if not giv 2mnvm2 +n² +1 2mnym² +n² +1 (m? + n2 + 4m m² +n² +m²n² + 1 \m² + n² + + tan-1 \m² +n² –m²n² + 1 Use the following figures for the calculation. Given, Each Corner Column = 400 + ID * 0.001 kips Each Exterior Column = 340 + ID * 0.001 kips Each Interior Column = 380 + ID * 0.001 kips 65 + ID * 0.001 35 + ID * 0.001

1. Find the settlements of the Mat Foundation and check angular rotation using Empirical Formula. Use any reasonable value if not giv 2mnvm2 +n² +1 2mnym² +n² +1 (m? + n2 + 4m m² +n² +m²n² + 1 \m² + n² + + tan-1 \m² +n² –m²n² + 1 Use the following figures for the calculation. Given, Each Corner Column = 400 + ID * 0.001 kips Each Exterior Column = 340 + ID * 0.001 kips Each Interior Column = 380 + ID * 0.001 kips 65 + ID * 0.001 35 + ID * 0.001

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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1. Find the settlements of the Mat Foundation and check angular rotation using Empirical Formula. Use any reasonable value if not given. 2mnvm? +n² +1 m² +n² –m²n²+1, 1 2mnvm2 +n² +1_ (m² + n? + 47 m2 +n² +m²n² + 1 \m² + n² + 1) + tan-1 Use the following figures for the calculation. Given, Each Corner Column = 400 + ID * 0.001 kips Each Exterior Column = 340 + ID * 0.001 kips Each Interior Column = 380 + ID * 0.001 kips 65 + ID * 0.001 35 + ID * 0.001
Transcribed Image Text:1. Find the settlements of the Mat Foundation and check angular rotation using Empirical Formula. Use any reasonable value if not given. 2mnvm? +n² +1 m² +n² –m²n²+1, 1 2mnvm2 +n² +1_ (m² + n? + 47 m2 +n² +m²n² + 1 \m² + n² + 1) + tan-1 Use the following figures for the calculation. Given, Each Corner Column = 400 + ID * 0.001 kips Each Exterior Column = 340 + ID * 0.001 kips Each Interior Column = 380 + ID * 0.001 kips 65 + ID * 0.001 35 + ID * 0.001
6 ft Silt y = 80 pcf 8 ft 6 ft Sand y = 100 pcf 20 ft Sand y = 110 pcf Clay y = 120 pcf C = 0.4 15 ft e, = 1.2 Rock
Transcribed Image Text:6 ft Silt y = 80 pcf 8 ft 6 ft Sand y = 100 pcf 20 ft Sand y = 110 pcf Clay y = 120 pcf C = 0.4 15 ft e, = 1.2 Rock
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