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1. Find the internal reactions (forces and moments) a 0.5 m 0.5 m A D OG H 0.6 m J B 0.2 m E 12 kN 25" 16 KN ↓ 0.4 m D

1. Find the internal reactions (forces and moments) a 0.5 m 0.5 m A D OG H 0.6 m J B 0.2 m E 12 kN 25" 16 KN ↓ 0.4 m D

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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**Educational Website Content** **Problem Statement:** 1. Find the internal reactions (forces and moments) at point J. **Diagram Explanation:** - The diagram illustrates a rigid L-shaped structure with several points marked from A to H. - The horizontal and vertical segments are joined at points A, B, D, and G, with each segment specified as having certain dimensions. - A horizontal force of 12 kN is applied at point C, directed to the right. - A vertical force of 16 kN is applied downward at point F. - The total height of the vertical segments is 1 m, divided into two 0.5 m parts between points A to D and D to G. - The base supporting the structure is located at G, which sits on a horizontal surface with a roller support at H. - The horizontal distance from G to H is 0.6 m. - The horizontal distance from D to E is 0.2 m, and from E to F, it's 0.4 m. - Point J is indicated between points D and G on a dashed line, located at 0.25 m from G down vertically and horizontally towards the right. This setup is used to analyze and calculate internal reactions at a specific point (J) using equilibrium equations. The analysis involves resolving the forces and moments acting on the structure. **Note:** The structure is subjected to two primary external loads, one vertical and one horizontal, which influence the internal reactions analyzed at point J.
Transcribed Image Text:**Educational Website Content** **Problem Statement:** 1. Find the internal reactions (forces and moments) at point J. **Diagram Explanation:** - The diagram illustrates a rigid L-shaped structure with several points marked from A to H. - The horizontal and vertical segments are joined at points A, B, D, and G, with each segment specified as having certain dimensions. - A horizontal force of 12 kN is applied at point C, directed to the right. - A vertical force of 16 kN is applied downward at point F. - The total height of the vertical segments is 1 m, divided into two 0.5 m parts between points A to D and D to G. - The base supporting the structure is located at G, which sits on a horizontal surface with a roller support at H. - The horizontal distance from G to H is 0.6 m. - The horizontal distance from D to E is 0.2 m, and from E to F, it's 0.4 m. - Point J is indicated between points D and G on a dashed line, located at 0.25 m from G down vertically and horizontally towards the right. This setup is used to analyze and calculate internal reactions at a specific point (J) using equilibrium equations. The analysis involves resolving the forces and moments acting on the structure. **Note:** The structure is subjected to two primary external loads, one vertical and one horizontal, which influence the internal reactions analyzed at point J.
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