1. Find the derivative of the following 9x²-4x+9 a)y = 2(x²-3)²√√3x-1

Q: The first derivative of f(x) 10x³ - 3 (5x4 - 6x)³ C. (3-10x³)√√(5x4 — 6x)³ A. = 5x² - 6x will be B.…

A: f(x)=15x4-6xwe know  (i) d dx(xn)=nxn-1

Q: (21 + V3)/3 11 dx Evaluate 50 + x - 14x

A: Explanation of the answer is as follows

Q: 1.Simplify: -2xy[6x² + {-6x³y – 2x²y – 2[2xy – x(3x²y– 3x – 2y) - 3x²] + 2x(xy)}– 3x²] a.

A: Topic:- Algebra

Q: S (et +3e²x) dx 2x 5+4et-e²x

A:

Q: 1. Simplify the following. a. f(x) =2x - 3 -2(5x-4) b. f(x) = (4x 2 - 5) +(-2x²+3x-5) c. A(r) -…

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Q: d, 3 Find dx -)- + x(х - 1)). A -3 +2х-1 B +1 -3 +1 -6 +2х-1 x3 (D

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Q: 3 2.)f x³ (4 + x²)² dx ; Use rationalizing substitution

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Q: (x - 3 bxy + 2 b?y?) (xdx + ydy) = xdy-ydx %3D

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Q: 5. S (3x-x²)dx x2

A: This is a problem related to integration. Based on the general formula and concept we will answer…

Q: Evaluate: 3 f(-x² + 4x-1)dx 1

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Q: 14) dx कर Vx2 - 8x - 9

A: Question - Evaluate the integral.

Q: find the constant term of (2x² + 1/x)⁹

A: find the constant term of (2x² + 1/x)⁹

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Q: 1. (a) Determine + 2x2 dx (b) Determine + 2x2 dx

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Q: For the function h(x) = −2x³ - 4x + 3√√x, calculate h'(x), h''(x), and h'''(x) . Show all steps. (2)…

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Q: 2sin(2x)=√3

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Q: 2 X 2 X 0+ - 4 +4 dx =

A: C+C

Q: √(x³ + 2x² + x -5) e 2X dx

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Q: DERIVE THE F. FUNCTIONS: s) y (x-3)(3x+4)(x²-2x+ 1)

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Q: x) = (1/3)x - 6

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Q: Solve for y. (4y + 7)* 13x + 15 19x - 15 (10y-37)'

A: 1) Opposite angles of a parallelogram are equal 2) Sum of all the interior angles is 360 degrees. In…

Q: Evaluate 1 √√3 X el-x² dx.

A: Given,            ∫13xe1-x2dx

Q: Evaluate V1-x-dx A. --(x+xvI– x-) +C B. (x+xV1%3=x) +C c. (x+xv1+x-) +C D. -(x-xVT-x-) + C xv1-x)+ C

A: Find your answer below

Q: 1. Differentiate: y = 3(²-1) A. (In 3) 3(x²-1) C. 2x (In 3) (3x²-1) B. (2x) 3(x²-1) D. x²(In…

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Q: 8x(x? + 1)3 dх .2 1)³dx -2 Inx 4. 1/4 xp() 3.

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Q: Find m/B. (4r + 11 (6x- 15

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Q: b) 2(x4+1)5 dx

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Q: (c) √[³√x + ]dx

A: The objective of the question is to find the integral of the square root of the cube root of x. This…