help me answer f-g please. A poll showed that when a sample of people in a certain country were asked whether they were thriving, struggling, or suffering, about 47% said they were thriving. Complete parts (a) through (h) below.a. Assuming the sample size was 800, how many in the sample said they were thriving?Assuming the sample size was 800, 376 in the sample said they were thriving.(Round to the nearest integer as needed.)b. Is the sample size large enough to apply the Central Limit Theorem? Explain. Assume the other conditions are met.Select the correct choice below and fill in the answer box(es) to complete your choice.(Round to the nearest integer as needed.)O A. Yes, the sample size is large enough, since the expected number of successes is 377 and the expected number of failures is 424, both of which are greater than or equal to 10.O B. Yes, the sample size is large enough, since the estimated standard error is , which is greater than or equal to 10.O C. No, the sample size is not large enough, since the expected number of successes isand the expected number of failures isat least one of which is less than 10.O D. No, the sample size is not large enough, since the estimated standard error iswhich is less than 10.c. Find a 95% confidence interval for the proportion that said they were thriving.The 95% confidence interval is ( | D.(Round to three decimal places as needed.)d. Find the width of the interval you found in part (c) by subtracting the lower limit from the upper limit.The width of the interval is(Round to three decimal places as needed.)e. Now assume the sample size was 3200. How many would have said they were thriving?Assuming the sample size was 3200,would have said they were thriving.(Round to the nearest integer as needed.)f. Find a 95% confidence interval for the proportion that said they were thriving using the numbers from part (e).The 95% confidence interval is ( | ):(Round to three decimal places as needed.)g. What is the width of the interval you found in part (f)?The width of the interval is(Round to three decimal places as needed.)

Name: help me answer f-g please. A poll showed that when a sample of people
Uploaded: 2022-12-08T14:54:05.000Z
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Description: help me answer f-g please. A poll showed that when a sample of people in a certain country were asked whether they were thriving, struggling, or suffering, about 47% said they were thriving. Complete parts (a) through (h) below.a. Assuming the sample

Given : A poll showed that when a sample of people in a certain country were asked they were thriving ,struggling , or suffering about 47 % . p=0.47f) The 95 % confidence interval is given by, The Z-value is obtained from z-score table Confidence interval=p^±Zα2×p^×1-p^np^=0.47 and (1-p^)=(1-0.47)=0.53Confidence interval=p^±Zα2×p^×1-p^nConfidence interval=0.47±1.96×0.47×0.533200Confidence interval=(0.452,0.487) The Z-value is obtained from z-score table We have α=0.05 level of significance At Z0.052=1.96 Answer : The 95% confidence interval the people were thriving is (0.452,0.487) g) To find the width of confidence interval found in f) Width of confidence interval=upper limit - lower limitWidth of confidence interval=0.487-0.452Width of confidence interval=0.035 Answer : The width of confidence interval is 0.035.