**Exercise 1: Two's Complement and Endianness****Objective:**Fill in the following table to show how the given integers are represented, assuming that 16 bits are used to store values and the machine uses two’s complement notation.**Table:**| Integer | Binary | Hex | 4 Byte Big Endian (hex value as seen in memory) | 4 Byte Little Endian (hex value as seen in memory) ||---------|--------|-----|-------------------------------------------------|----------------------------------------------------|| 28 | | | | || 2216 | | | | || -18675 | | | | || -12 | | | | || 31456 | | | | |**Instructions:**1. Convert each integer to its 16-bit binary representation in two's complement format.2. Convert the binary representation to hexadecimal.3. Use the hexadecimal value to determine the big-endian and little-endian representations, assuming a 4-byte representation for each number.**Notes:**- **Two's Complement**: A method for representing signed integers that can accommodate both positive and negative values.- **Endianness**: - **Big Endian**: Stores the most significant byte at the smallest memory address. - **Little Endian**: Stores the least significant byte at the smallest memory address.

Introduction : Binary is a base 2 number system that uses two digits, 0 and 1. Hexadecimal is a base 16 number system that uses 16 different digits, 0-9 and A-F. Big-endian is a type of byte ordering where the most significant byte (the "big end") is stored first, while little endian is the opposite where the least significant byte is stored first.Answer : 28 First, convert the given value into binary form,28(binary value)=0000000000011100The hexadecimal format of 28 can be written by splitting the binary form of 28 into 4 bits and then writing the equivalent hexadecimal value,0000 0000 0001 1100 = 001c 2216 2216(binary value)-0000100010101000=08A8The hexadecimal format of 2216 can be written by splitting the binary form of 28 into 4 bits and then writing the equivalent hexadecimal value,0000 1000 1010 1000 = 08A8 -18675 -18675=-(18675) Since the given value is a negative value, convert it into binary form and then take two's complement.-18675--(0100100011110011) 1's complement=1011011100001100 -12 -12 = -(12) Since the given value is negative value, convert it into binary form and then take two's complement.-12=-(0000000000001100)I's complement-11111111111100112's complement=1111111111110100Hexadecimal format of -(12) can be written by splitting the binary form of 28 into 4 bits and then write the equivalent hexadecimal value,1111 1111 1111 0100 = FFF4 31456 31456(binary value)=0111101011100000Hexadecimal format of 31456 can be written by splitting the binary form of 28 into 4 bits and then write the equivalent hexadecimal value,0111 1010 1110 0000 = 7AE0The final answer is - Integer Binary Hexadecimal Big Endian Hex Little Endian Hex 28 0000 0000 0001 1100 001C 0001C 1C00 2216 0000 1000 1010 1000 08A8 08A8 A808 -18675 1011 0111 0000 1101 B70D B70D 0DB7 -12 1111 1111 1111 0100 FFF4 FFF4 F4FF 31456 0111 1010 1110 0000 7AE0 7AE0 E07A

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Computer Science

1. Fill in the following table to show how the given integers are represented, assuming that 16 bits are used to store values and the machine used two's complement notation. Integer 28 2216 -18675 -12 31456 Binary Hex 4 Byte Big Endian (hex value as seen in memory) 4 Byte Little Endian (hex value as seen in memory)

1. Fill in the following table to show how the given integers are represented, assuming that 16 bits are used to store values and the machine used two's complement notation. Integer 28 2216 -18675 -12 31456 Binary Hex 4 Byte Big Endian (hex value as seen in memory) 4 Byte Little Endian (hex value as seen in memory)

Database System Concepts

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ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Concept explainers

Random Access

Random access is generally known as direct access. Random access is the capability to have access to any item from a given population of elements at random. Sequential access is the direct opposite of random access. In random access, the elements can be retrieved irrespective of the location. In order to move from point A to Z, you can just jump to point Z in random access system. The disk is an example of random access.

Question

**Exercise 1: Two's Complement and Endianness**

**Objective:**
Fill in the following table to show how the given integers are represented, assuming that 16 bits are used to store values and the machine uses two’s complement notation.

**Table:**

| Integer | Binary | Hex | 4 Byte Big Endian (hex value as seen in memory) | 4 Byte Little Endian (hex value as seen in memory) |
|---------|--------|-----|-------------------------------------------------|----------------------------------------------------|
| 28 | | | | |
| 2216 | | | | |
| -18675 | | | | |
| -12 | | | | |
| 31456 | | | | |

**Instructions:**
1. Convert each integer to its 16-bit binary representation in two's complement format.
2. Convert the binary representation to hexadecimal.
3. Use the hexadecimal value to determine the big-endian and little-endian representations, assuming a 4-byte representation for each number.

**Notes:**
- **Two's Complement**: A method for representing signed integers that can accommodate both positive and negative values.
- **Endianness**:
- **Big Endian**: Stores the most significant byte at the smallest memory address.
- **Little Endian**: Stores the least significant byte at the smallest memory address.

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