1. Figure 1 shows the partial datasheet for a 2N5458 JFET. Based on datasheet in Figure I obtain the value of typical Inss and maximum Vosom Use these values to calculate the drain current for Vos -0 V, -2 V, and -3 V. 2. JFET biasing is used to select the proper de gate-to-source voltage to establish a desired value of drain current and thus a proper Q-point. To illustrate JFET biasing circuit, sketch the self-biased n-channel JFET. If the given the parameter values of lb-8 mA, Rp = 2.0 ka, Ra = 10 MN, Rs = 280 2 and VDD =24 V, determine Vps and Vos

Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
icon
Related questions
icon
Concept explainers
Question
Answer question 1 and 2 in 30 minute
1. Figure 1 shows the partial datasheet for a 2N5458 JFET. Based on datasheet in Figure
1 obtain the value of typical Ipss and maximum VGs(om Use these values to calculate
the drain current for Vos -0 V, -2 V, and -3 V.
2. JFET biasing is used to select the proper de gate-to-source voltage to establish a desired
value of drain current and thus a proper Q-point. To illustrate JFET biasing circuit,
sketch the self-biased n-channel JFET. If the given the parameter values of Ip - 8 mA,
Rp = 2.0 ka, Rg = 10 MQ, Rs = 280 2 and Vpp =24 V, determine Vps and Vos
Transcribed Image Text:1. Figure 1 shows the partial datasheet for a 2N5458 JFET. Based on datasheet in Figure 1 obtain the value of typical Ipss and maximum VGs(om Use these values to calculate the drain current for Vos -0 V, -2 V, and -3 V. 2. JFET biasing is used to select the proper de gate-to-source voltage to establish a desired value of drain current and thus a proper Q-point. To illustrate JFET biasing circuit, sketch the self-biased n-channel JFET. If the given the parameter values of Ip - 8 mA, Rp = 2.0 ka, Rg = 10 MQ, Rs = 280 2 and Vpp =24 V, determine Vps and Vos
FIGURE 1
Electrical Characteristics
TA2Ciethurated
Symbol
Min Typ Max Units
Туp Маx |Units
Parameter
Test Conditions
OFF CHARACTERISTICS
Vas
-25
Gate-Source Breakdown Voltage
Gate Reverse Current
la = 10A, Vos =0
Von =-15 V, Voe =0
Vos = -15 V, Ves =0, Ta 100'C
Vog= 15 V. e = 10 NA
lass
1.0
-200
-6.0
-7.0
-8.0
nA
nA
Vasn
Gate-Source Cutoff Voltage
5457
5458
5459
0.5
- 1.0
-20
V
Vos
Gate Source Voitage
Vos = 15 V, le = 100 A
Vos = 15 V, lo= 200 A
Von 15 V, = 400 A 5459
-25
-3.5
4.5
5457
5450
ONCHARACTERISTICS
Zero-Gate Voltage Drain Currenit
Vos = 15 V, Vas = 0
6.0
9.0
16
loss
5457
1.0
5458
S450
20
4.0
3.0
6.0
9.0
mA
mA
SMALL SIGNAL CHARACTERISTICS
Forward Transter Conductarice
Vos= 15 V, Vos =0,1=1.0 KHZ
5457
5000 umhos
5500 umhos
6000 mhos
50 umhos
7.0 pF
3.0 DF
3.0
5458
5459
1000
1500
2000
Output Conductance
input Capacitance
Reverse Transter Capacitance
Vos = 15 V, Vas =0,1= 1,0 kHZ
Vos = 15 V, Vas =0, =1.0 MHE
Vos = 15 V, Vos =0, 1= 1.0 MH2
Von = 15 V, Vos = 0,1= 1.0 KHZ.
Re 1.0 megchm. BW = 1.0 Hz
10
Cas
4.5
1.5
Csa
NF
Noise Figure
* et WMah300 m, Dy Cyes
Transcribed Image Text:FIGURE 1 Electrical Characteristics TA2Ciethurated Symbol Min Typ Max Units Туp Маx |Units Parameter Test Conditions OFF CHARACTERISTICS Vas -25 Gate-Source Breakdown Voltage Gate Reverse Current la = 10A, Vos =0 Von =-15 V, Voe =0 Vos = -15 V, Ves =0, Ta 100'C Vog= 15 V. e = 10 NA lass 1.0 -200 -6.0 -7.0 -8.0 nA nA Vasn Gate-Source Cutoff Voltage 5457 5458 5459 0.5 - 1.0 -20 V Vos Gate Source Voitage Vos = 15 V, le = 100 A Vos = 15 V, lo= 200 A Von 15 V, = 400 A 5459 -25 -3.5 4.5 5457 5450 ONCHARACTERISTICS Zero-Gate Voltage Drain Currenit Vos = 15 V, Vas = 0 6.0 9.0 16 loss 5457 1.0 5458 S450 20 4.0 3.0 6.0 9.0 mA mA SMALL SIGNAL CHARACTERISTICS Forward Transter Conductarice Vos= 15 V, Vos =0,1=1.0 KHZ 5457 5000 umhos 5500 umhos 6000 mhos 50 umhos 7.0 pF 3.0 DF 3.0 5458 5459 1000 1500 2000 Output Conductance input Capacitance Reverse Transter Capacitance Vos = 15 V, Vas =0,1= 1,0 kHZ Vos = 15 V, Vas =0, =1.0 MHE Vos = 15 V, Vos =0, 1= 1.0 MH2 Von = 15 V, Vos = 0,1= 1.0 KHZ. Re 1.0 megchm. BW = 1.0 Hz 10 Cas 4.5 1.5 Csa NF Noise Figure * et WMah300 m, Dy Cyes
Expert Solution
steps

Step by step

Solved in 3 steps with 2 images

Blurred answer
Knowledge Booster
Antenna Characteristics
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, electrical-engineering and related others by exploring similar questions and additional content below.
Similar questions
Recommended textbooks for you
Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
Electrical Engineering
ISBN:
9780133923605
Author:
Robert L. Boylestad
Publisher:
PEARSON
Delmar's Standard Textbook Of Electricity
Delmar's Standard Textbook Of Electricity
Electrical Engineering
ISBN:
9781337900348
Author:
Stephen L. Herman
Publisher:
Cengage Learning
Programmable Logic Controllers
Programmable Logic Controllers
Electrical Engineering
ISBN:
9780073373843
Author:
Frank D. Petruzella
Publisher:
McGraw-Hill Education
Fundamentals of Electric Circuits
Fundamentals of Electric Circuits
Electrical Engineering
ISBN:
9780078028229
Author:
Charles K Alexander, Matthew Sadiku
Publisher:
McGraw-Hill Education
Electric Circuits. (11th Edition)
Electric Circuits. (11th Edition)
Electrical Engineering
ISBN:
9780134746968
Author:
James W. Nilsson, Susan Riedel
Publisher:
PEARSON
Engineering Electromagnetics
Engineering Electromagnetics
Electrical Engineering
ISBN:
9780078028151
Author:
Hayt, William H. (william Hart), Jr, BUCK, John A.
Publisher:
Mcgraw-hill Education,