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1. Explain the following differences in pka. a. Diphenylmethanol vs. isopropanol OH pka= Ph c. Phenol vs. BHT b. Benzylammonium vs. anilinium pka= 9.3 pka= Ph 13.6 OH 5 9.88 NH3 OH OH 4.6 12.75 17.1 -NH3

1. Explain the following differences in pka. a. Diphenylmethanol vs. isopropanol OH pka= Ph c. Phenol vs. BHT b. Benzylammonium vs. anilinium pka= 9.3 pka= Ph 13.6 OH 5 9.88 NH3 OH OH 4.6 12.75 17.1 -NH3

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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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1. Explain the following differences in pka. a. Diphenylmethanol vs. isopropanol OH pka= pka= c. Phenol vs. BHT Ph b. Benzylammonium vs. anilinium pka= OH 9.88 Ph 13.6 9.3 NH3 OH K 17.1 4.6 -NH3 OH ** 12.75
Transcribed Image Text:1. Explain the following differences in pka. a. Diphenylmethanol vs. isopropanol OH pka= pka= c. Phenol vs. BHT Ph b. Benzylammonium vs. anilinium pka= OH 9.88 Ph 13.6 9.3 NH3 OH K 17.1 4.6 -NH3 OH ** 12.75
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1) 

a - Diphenylmethanol vs isopropanol - 

Pka value is negative logarithm of ka . Higher the ka value higher will be acidity and hence lower will be pka value . 
so higher the pka value lower will be ka value and lower will be acidity .  
In diphenylmethanol two phenyl groups are attached due to which it’s acidity increases due to resonance and hence ka value increase and pka will decrease. While in isopropanol ch3 groups are attached so it show +I effect and as compared to phenyl group it show less acidity and hence pka value is more . 
 
Pka value = isopropanol > diphenylmethanol . 

                     17.1.                   13.6                  

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