need help please understanding this question!!Experiments show that the solubility of alum under conditions used in this lab is about 1.0g at 1.0 c and 1.7 at 6.0 c. Using your measured solution temperature, estimate the amount of alum left in your chilled solution according to the graph. Thank you very much!! I have no idea how to set it up and in case this shows up on an exam, I want to know how to do it!! Thank you!!!! 9.48 182Questions1. Experiments show that the solubility of alum under the conditions used in this lab is about 1.0 gat 1.0 °C and 1.7 g at 6.0 °C. Using your measured solution temperature, estimate the amount ofalum left in your chilled solution according to the graph shown:Effect of temperature on alumsolubility1.7 gY=MX+Cy = 0.14x + 0.861.51.0 gAlum left in1solution (g)0.50.14Temperature (°C)3.5Alum left in solution: . 351.35°CTemperature of alum solutionHosteY=0.143/ x3.5c to,86=2. Does the amount of alum left in solution account for most of the difference between themaximum grams of alum and your experimental grams of alum? Explain:2.2. 0.5433:5"109.18116.277.09Mass of aluminum foil used°CTemperature of cooled alum solutionMass of empty 150-mL (or 250-mL) beakerMass of 150-mL (or 250-mL) beaker + dried alum crystalsMass of alum obtained%3D116.275 109.18 7.0956.For the following, show your calculations:

When the amount of solute is dissolved in a solvent to make a homogenous mixture are known as…

Answered: 1. Experiments show that the solubility…

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Experiments show that the solubility of alum under conditions used in this lab is about 1.0g at 1.0 c and 1.7 at 6.0 c. Using your measured solution temperature, estimate the amount of alum left in your chilled solution according to the graph. Thank you very much!! I have no idea how to set it up and in case this shows up on an exam, I want to know how to do it!! Thank you!!!!

9.48 182
Questions
1. Experiments show that the solubility of alum under the conditions used in this lab is about 1.0 g
at 1.0 °C and 1.7 g at 6.0 °C. Using your measured solution temperature, estimate the amount of
alum left in your chilled solution according to the graph shown:
Effect of temperature on alum
solubility
1.7 g
Y=MX+C
y = 0.14x + 0.86
1.5
1.0 g
Alum left in
1
solution (g)
0.5
0.
1
4
Temperature (°C)
3.5
Alum left in solution: . 35
1.35
°C
Temperature of alum solution
Hoste
Y=0.143/ x3.5c to,86=
2. Does the amount of alum left in solution account for most of the difference between the
maximum grams of alum and your experimental grams of alum? Explain:
2.
2.

0.543
3:5"
109.18
116.27
7.09
Mass of aluminum foil used
°C
Temperature of cooled alum solution
Mass of empty 150-mL (or 250-mL) beaker
Mass of 150-mL (or 250-mL) beaker + dried alum crystals
Mass of alum obtained
%3D
116.275 109.18 7.095
6.
For the following, show your calculations:

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