1. Each of the following functions undergoes a bifurcation of fixed points at the given parameter value. In each case, use algebraic or graphical methods to identify this bifurcation as either a saddle-node or period-doubling bifurcation, or neither of these. In each case, sketch the phase portrait for typical parameter values below, at, and above the bifurcation value. a. F,(x) =1+r²+ A, a = 0 b. Fx(x) =1+r²+ A, a = -1 c. G„(z) = µx+r', µ= -1 d. G„(z) = µx+r², µ = 1 e. Sp(x) = µ sin r, µ = 1 f. Sp(x) = µsin I, µ = -1 g. F.(z) = r³ + c, c = 2/3/3 h. Ex(r)= (e² – 1), A= -1 i. Ex(x) = (e² – 1), A=1 %3D

Advanced Engineering Mathematics
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Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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1. Each of the following functions undergoes a bifurcation of fixed points at
the given parameter value. In each case, use algebraic or graphical methods to
identify this bifurcation as either a saddle-node or period-doubling bifurcation,
or neither of these. In each case, sketch the phase portrait for typical parameter
values below, at, and above the bifurcation value.
a. Fx(x) = 1+r² + A, a = 0
b. Fx(x) = x + a² + A, a = -1
c. G„(x) = µr +r³, µ = -1
d. G, (1 ) = μπ + π', μ=1
e. S„(1) = µ sin r, µ= 1
f. S„(r) = u sin r, µ= -1
g. Fe(r) = r³ + c, c = 2/3/3
h. Ex(r) = Me* – 1), A= -1
i. Ex(r) = Me – 1), A= 1
j. He(r) = r + cr², c = 0
k. F.(r) = r+cz² + x³, c = 0
Transcribed Image Text:1. Each of the following functions undergoes a bifurcation of fixed points at the given parameter value. In each case, use algebraic or graphical methods to identify this bifurcation as either a saddle-node or period-doubling bifurcation, or neither of these. In each case, sketch the phase portrait for typical parameter values below, at, and above the bifurcation value. a. Fx(x) = 1+r² + A, a = 0 b. Fx(x) = x + a² + A, a = -1 c. G„(x) = µr +r³, µ = -1 d. G, (1 ) = μπ + π', μ=1 e. S„(1) = µ sin r, µ= 1 f. S„(r) = u sin r, µ= -1 g. Fe(r) = r³ + c, c = 2/3/3 h. Ex(r) = Me* – 1), A= -1 i. Ex(r) = Me – 1), A= 1 j. He(r) = r + cr², c = 0 k. F.(r) = r+cz² + x³, c = 0
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