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1. e* = 17.54 3. 2e¹x = 15 5. e* - 1 = 6 2. e²x - 5 = 14 4. ex+15=0 6. e²x + 5 = 0

1. e* = 17.54 3. 2e¹x = 15 5. e* - 1 = 6 2. e²x - 5 = 14 4. ex+15=0 6. e²x + 5 = 0

Algebra and Trigonometry (6th Edition)
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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7. 3.12x - 4 = 16 8. 4(10%) + 24 = -16 and em = e^n, then In(m) = ln(n). In order solve exponential functions involving the irrational number and natural logarithmic base e, we instead take the natural logarithm on both sides of the equation. Therefore, if m and n are both positive Solve the equation e* - 5 = 14. Example 3: Step 1: Step 2: Step 3: Step 4: Problem Set B: Solve and check the following equations: 1. e* = 17.54 3. 2e4x = 15 5. ex-1=6 ex-5=14 ex-5+5=14+5 ex=19 In (ex) = In (19) X=In (19) = 2.944 2. e²x - 5 = 14 4. ex+¹-5=0 for Math 096 6. e²x + 5 = 0
Transcribed Image Text:7. 3.12x - 4 = 16 8. 4(10%) + 24 = -16 and em = e^n, then In(m) = ln(n). In order solve exponential functions involving the irrational number and natural logarithmic base e, we instead take the natural logarithm on both sides of the equation. Therefore, if m and n are both positive Solve the equation e* - 5 = 14. Example 3: Step 1: Step 2: Step 3: Step 4: Problem Set B: Solve and check the following equations: 1. e* = 17.54 3. 2e4x = 15 5. ex-1=6 ex-5=14 ex-5+5=14+5 ex=19 In (ex) = In (19) X=In (19) = 2.944 2. e²x - 5 = 14 4. ex+¹-5=0 for Math 096 6. e²x + 5 = 0
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