1. Drops frequently form above the ocean by the mechanical disruption of waves in strong winds. How much work is required to break up 1 kg of seawater (T = 20°C, s=35 psu) into tiny drops (called spray drops), each in the form a sphere with radius 1 μm? The surface tension between seawater and air can be evaluated from σ (air-seawater) = 75.63 -0.144 T+ 0.221 s where T is in °C, s is in psu, and σis 10-3 Nm-1.
1. Drops frequently form above the ocean by the mechanical disruption of waves in strong winds. How much work is required to break up 1 kg of seawater (T = 20°C, s=35 psu) into tiny drops (called spray drops), each in the form a sphere with radius 1 μm? The surface tension between seawater and air can be evaluated from σ (air-seawater) = 75.63 -0.144 T+ 0.221 s where T is in °C, s is in psu, and σis 10-3 Nm-1.
College Physics
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Chapter1: Units, Trigonometry. And Vectors
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![1. Drops frequently form above the ocean by the mechanical disruption of waves in
strong winds. How much work is required to break up 1 kg of seawater (T = 20°C,
s=35 psu) into tiny drops (called spray drops), each in the form a sphere with radius
1 μm? The surface tension between seawater and air can be evaluated from
σ(air-seawater) = 75.63 -0.144 T+ 0.221 s
where T is in ºC, s is in psu, and σ is 10-3 N m-¹.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fbc7c60f4-b738-4960-a3bb-92dbce1568e3%2F1f0c5318-e8f9-47d1-9e51-75b5e08ae052%2Fsyemgo_processed.png&w=3840&q=75)
Transcribed Image Text:1. Drops frequently form above the ocean by the mechanical disruption of waves in
strong winds. How much work is required to break up 1 kg of seawater (T = 20°C,
s=35 psu) into tiny drops (called spray drops), each in the form a sphere with radius
1 μm? The surface tension between seawater and air can be evaluated from
σ(air-seawater) = 75.63 -0.144 T+ 0.221 s
where T is in ºC, s is in psu, and σ is 10-3 N m-¹.
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