1. Draw sketch graphs of the functions: g) y-9-4² h) y-9-3¹
Trigonometry (11th Edition)
11th Edition
ISBN:9780134217437
Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Chapter1: Trigonometric Functions
Section: Chapter Questions
Problem 1RE:
1. Give the measures of the complement and the supplement of an angle measuring 35°.
Related questions
Question
![### Exercise 8.1
#### 1. Draw sketch graphs of the functions:
- (Function in subpart (a) is not visible due to obscuring)
- \( y = 9 - 4x^2 \)
- \( y = 9 - 3^x \)
#### 2. Match each graph to one equation:
\[ y = ax + q, \quad y = ax^2 + q, \quad y = \frac{a}{x} + q, \quad y = ax^k + q \]
and one condition:
- (i) \( a > 0, q > 0 \)
- (ii) \( a > 0, q = 0 \)
- (iii) \( a > 0, q < 0 \)
- (iv) \( a < 0, q > 0 \)
- (v) \( a < 0, q = 0 \)
- (vi) \( a < 0, q < 0 \)
#### Graphs:
**a)** This graph appears to be a downward-opening parabola with its vertex at the origin \((0,0)\). This could be represented by an equation of the form \( y = ax^2 + q \) where \( a < 0 \) since it opens downwards and the condition \( q = 0 \) might apply given its vertex is at the origin.
**b)** This graph shows a rational function with both horizontal and vertical asymptotes. The graph has an asymptote at \( y = 0 \) and the curve approaches the asymptote as \( x \to \infty \). This suggests the equation is of the form \( y = \frac{a}{x} + q \) with the condition \( q < 0 \).
**c)** This graph is an upward-sloping line passing through the origin, which indicates a linear function. The general form is \( y = ax + q \) with the condition \( q = 0 \).
**d)** This graph shows a rational function with a vertical asymptote and a horizontal asymptote at \( y = 0 \). The graph seems to decrease horizontally to the right, suggesting \( a < 0 \) and \( q = 0 \).
**e)** This graph resembles the second part of a parabola opening downward and](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe295181f-f552-4661-a8ed-41c7c998dd9d%2F6179ab39-db9e-4824-9b25-5894e87c0084%2Flfn0w5g_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Exercise 8.1
#### 1. Draw sketch graphs of the functions:
- (Function in subpart (a) is not visible due to obscuring)
- \( y = 9 - 4x^2 \)
- \( y = 9 - 3^x \)
#### 2. Match each graph to one equation:
\[ y = ax + q, \quad y = ax^2 + q, \quad y = \frac{a}{x} + q, \quad y = ax^k + q \]
and one condition:
- (i) \( a > 0, q > 0 \)
- (ii) \( a > 0, q = 0 \)
- (iii) \( a > 0, q < 0 \)
- (iv) \( a < 0, q > 0 \)
- (v) \( a < 0, q = 0 \)
- (vi) \( a < 0, q < 0 \)
#### Graphs:
**a)** This graph appears to be a downward-opening parabola with its vertex at the origin \((0,0)\). This could be represented by an equation of the form \( y = ax^2 + q \) where \( a < 0 \) since it opens downwards and the condition \( q = 0 \) might apply given its vertex is at the origin.
**b)** This graph shows a rational function with both horizontal and vertical asymptotes. The graph has an asymptote at \( y = 0 \) and the curve approaches the asymptote as \( x \to \infty \). This suggests the equation is of the form \( y = \frac{a}{x} + q \) with the condition \( q < 0 \).
**c)** This graph is an upward-sloping line passing through the origin, which indicates a linear function. The general form is \( y = ax + q \) with the condition \( q = 0 \).
**d)** This graph shows a rational function with a vertical asymptote and a horizontal asymptote at \( y = 0 \). The graph seems to decrease horizontally to the right, suggesting \( a < 0 \) and \( q = 0 \).
**e)** This graph resembles the second part of a parabola opening downward and
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