1. Dr. Poage has decided to produce and sell rings that say "-1 O MATH!" The price-demand equation and cost function to produce these rings are given respectively by: +200 C(x) = 72000+ 60x, where x is the number of rings that can be sold at a price of Sp per p=-- 30 ring and C(x) is the total cost (in dollars) of producing x rings. (a) Determine the break-even point(s). uoubong sgo bna Lori aum brw amroHO (bnew an ot bruc) nond o (b) What is the maximum Revenue? (c) How many rings are needed to maximize the Revenue? itong asi d) What should the rings be priced at to maximize the Revenue? of e boing od abrer odr bluone paw e) Find the Profit function and simplify. T0OS s ey noises snslio0-nevitl to noialugoq orti aloborm 002.001 alunl odr 9000.02 focoi noltalugoq orli bfbow 1oy mdw gnid (S00S 1say adti 0 ) How many rings are needed to maximize the Profit? g) What is the maximum profit?
1. Dr. Poage has decided to produce and sell rings that say "-1 O MATH!" The price-demand equation and cost function to produce these rings are given respectively by: +200 C(x) = 72000+ 60x, where x is the number of rings that can be sold at a price of Sp per p=-- 30 ring and C(x) is the total cost (in dollars) of producing x rings. (a) Determine the break-even point(s). uoubong sgo bna Lori aum brw amroHO (bnew an ot bruc) nond o (b) What is the maximum Revenue? (c) How many rings are needed to maximize the Revenue? itong asi d) What should the rings be priced at to maximize the Revenue? of e boing od abrer odr bluone paw e) Find the Profit function and simplify. T0OS s ey noises snslio0-nevitl to noialugoq orti aloborm 002.001 alunl odr 9000.02 focoi noltalugoq orli bfbow 1oy mdw gnid (S00S 1say adti 0 ) How many rings are needed to maximize the Profit? g) What is the maximum profit?
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question
How do I solve the following problem?
Expert Solution
Step 1
Price demand equation is
(1)
and cost function is
(2)
So Revenue function is
Here x is the number of rings.
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