cal 8 - EFBC2524...Favouriteslearn-eu-central-1-prod-fl...Practical 8Practical 81.Die onderdom (X) en bloeddruk (Y) van 9 pasiënte is gemeet en die resultate was asvolg: / The age (X) and blood pressure (Y) of 9 patients were measured and the resultsare as follows:Patient/ Pasiënt Age (X) / Ouderdom (X)Blood pressure (Y) / Bloeddruk (Y)1912225125330126442129461306.52135571388.621429.701451.1 Konstrueer 'n puntdiagram vir die data. / Produce a scatterplot of the data.Vind die lineêre regressielyn om die bloeddruk vanaf ouderdom met behulp van diemetode van kleinste kwadrate te beraam, d.w.s. vind. Trek die lyn op die puntdiagram. /Find the linear regression line to estimate blood pressure from age by the method of leastsquares, i.e. find:. Draw the line on the scatterplot.1.2Wat is die beraamde bloeddruk van 'n pasiënt met ouderdom 35? / What is theestimated blood pressure of a patient aged 35?1.31.4Bepaal / Find SSE.1.5Bepaal / Find1.6Bepaal 'n 95% vertrouensinterval vir / Determine a 95% confidence interval for1.7Toets die hiptotese teenoor die alternatief. / Test the hypothesis against the alternative1.8Stel 'n 95% vertrouensinterval vir die gemiddelde bloeddruk van 'n persoon wat 35jaaroud is op. construct a 95% confidence interval for the mean blood pressure of a personthat is 35 years old.Bereken die korrelasie tussen die ouderdom en bloeddruk data. / Calculate thecorrelation between the age and blood pressure data.1.91.10Bepaal die bepaaldheidkoëffisiënt. / Determine the cefficient of determination.1.11Toets die hiptotese teenoor die alternatief. / Test the hypothesis against thealternativeA marine biologist wants to test the efffect of water temnerature (in Con the nverage

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Answered: 1. Die onderdom (X) en bloeddruk (Y)…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The distribution of IQ scores of the population is normally distributed with a mean of 100 and a standard deviation of 15 for a particular data value. Since the population is normally distributed all sampling distributions will also be normally distributed. Find the z-scores for each of the following. Make sure to pay attention to the distribution you should use. Write exact answers as decimals. A single person with an IQ of 121: Z-score = Mean of a sample of 4 IQ's is 121: Z-score = 2.80 Mean of a sample of 9 IQ's is 121: Z-score = 1.40 Mean of a sample of 25 IQ's is 121: Z-score = 4.20 Mean of a sample of 100 IQ's is 121: Z-score = Mean of a sample of 625 IQ's is 121: Z-score = 7.00 14.00 35.00
Assume that a randomly selected subject is given a bone density test. Those test scores are normally distributed with a mean of 0 and a standard deviation of 1. Draw a graph and find the probability of a bone density test score greater than 3.85. Sketch the region. Choose the correct graph below. O A. -3.85 B. The probability of a bone density test score greater than - 3.85 is (Round to four decimal places as needed.) 3.85 ^ 3.85 A -3.85
Please solve for p value ,determine weather to reject hypothesis and state the conclusion for enough evidence
The following table gives data for the velocity of a sports car accelerating from 0 to 193 miles per hour over the course of 36 seconds (10 thousandths of an hour).
Suppose X~N(186,19) and Z~N(0,1). If z = 1.24, what is it on an X scale? Express your answer to two decimal places (ex: 123.45).
Professor Ramos has a packing plant in a machine packs carton with jars. A sales person claims that the machine she is selling will pack faster to test the claim the times It takes each machine to pack 10 cartons are recorded in seconds and the results are shown below population one new machine n=10 Mean =42.3 s=0.685 Present machine n=10 mean=43.23 S =0.750.Do the data provide significant evidence to conclude that on the average the new machine packs faster perform the required hypothesis test in the 5% level of significance assume the population standard deviation's are equal but unknown show all your steps setting up your null and alternative hypothesis.
CHECK ALL THAT APPLIES PLEASE CORRECT ANSWER.
Overproduction of uric acid in the body can be an indication of cell breakdown. This may be an advance indication of illness such as gout, leukemia, or lymphoma.† Over a period of months, an adult male patient has taken fifteen blood tests for uric acid. The mean concentration was x = 5.40 mg/dl. The distribution of uric acid in healthy adult males can be assumed to be normal, with ? = 1.89 mg/dl. (a) Find a 95% confidence interval for the population mean concentration of uric acid in this patient's blood. What is the margin of error? (Round your answers to two decimal places.) lower limit= upper limit= margin of error= (b) What conditions are necessary for your calculations? (Select all that apply.) normal distribution of uric acid ? is unknown uniform distribution of uric acid n is large ? is known (c) Interpret your results in the context of this problem. We are 95% confident that the true uric acid level for this patient falls within this interval.The probability…
The body weight of a healthy 3-month old colt should be about µ = test the claim that the weight of a wild Nevada colt (3-months old) is more than 60 kg. 60kg Suppose you want to State in words what a Type I Error is. State the mean weight of a wild Nevada (3-month old) colt is less than 60 Kg when in fact the mean weight of a wild Nevada colt (3-month old) is more than or equal to 60 kg. State the mean weight of a wild Nevada (3-month old) colt is more than 60 Kg when in fact the mean weight of a wild Nevada colt (3-month old) is less than or equal to 60 kg. State the mean weight of a wild Nevada (3-month old) colt is equal to 60 Kg when in fact the mean weight of a wild Nevada colt (3-month old) is not equal to 60 kg. State the mean weight of a wild Nevada (3-month old) colt is less than or equal to 60 Kg when in fact the mean weight of a wild Nevada colt (3-month old) is more than 60 kg.
In 2017, the entire fleet of light‑duty vehicles sold in the United States by each manufacturer must emit an average of no more than 9090 milligrams per mile (mg/mi) of nitrogen oxides (NOX) and nonmethane organic gas (NMOG) over the useful life (150,000150,000 miles of driving) of the vehicle. NOX ++ NMOG emissions over the useful life for one car model vary Normally with mean 8484 mg/mi and standard deviation 66 mg/mi. (a) What is the probability that a single car of this model emits more than 9090 mg/mi of NOX ++ NMOG? (Enter your answer rounded to four decimal places.) (b) A company has 1616 cars of this model in its fleet. What is the probability that the average NOX ++ NMOG level ?¯x¯ of these cars is above 9090 mg/mi? (Enter your answer rounded to four decimal places.)

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