Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
![**Question:**
Determine the number of electrons necessary to equal a mass of \(1.15 \times 10^2\) grams.
**Solution:**
To solve this problem, we need to know the mass of an individual electron. The mass of one electron is approximately \(9.11 \times 10^{-28}\) grams. By dividing the total mass by the mass of one electron, we can find the number of electrons required.
\[
\text{Number of electrons} = \frac{1.15 \times 10^2 \text{ grams}}{9.11 \times 10^{-28} \text{ grams/electron}}
\]
Calculate the above division to find the solution.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F735d22c9-cf67-4912-9354-60bc99af824f%2F6b39cd8f-890f-4e4a-bdd9-d856bc5856fb%2Fy3284cjc_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Question:**
Determine the number of electrons necessary to equal a mass of \(1.15 \times 10^2\) grams.
**Solution:**
To solve this problem, we need to know the mass of an individual electron. The mass of one electron is approximately \(9.11 \times 10^{-28}\) grams. By dividing the total mass by the mass of one electron, we can find the number of electrons required.
\[
\text{Number of electrons} = \frac{1.15 \times 10^2 \text{ grams}}{9.11 \times 10^{-28} \text{ grams/electron}}
\]
Calculate the above division to find the solution.
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