1.) Please help with question and provide free body diagrams when needed **Problem Statement:**1. Determine the force in each member of the truss shown below. Indicate whether the members are in tension or compression. Let \( P_1 = 350 \) lbs and \( P_2 = 600 \) lbs.**Diagram Explanation:**The diagram depicts a simple triangular truss structure with points labeled A, B, and C. The truss consists of the following members:- Member AB: Connects point A to B, with a vertical height of 4 feet.- Member BC: Connects point B to C, horizontal distance of 8 feet.- Member AC: Connects point A to C, horizontal distance of 13 feet (combined from 5 ft to B plus 8 ft to C).Forces Applied:- \( P_1 = 350 \) lbs acts downward at point B.- \( P_2 = 600 \) lbs acts horizontally to the right at point B.Supports:- Point A is supported by a pinned support that can provide both vertical and horizontal reaction forces.- Point C is supported by a roller support, allowing horizontal movement but providing a vertical reaction force.The truss problem requires calculating the forces in each member (AB, BC, and AC) and determining if they are in tension or compression.

Truss: A truss is a structure that is formed with two force members. The members are connected by joints and a truss structure is formed which is used in construction of bridges, roofs, etc. Given Data: A truss is given as: P1=350IbsP2=600IbsCalculate Forces in Each Member: The forces in each member are calculated as given below: The angles are calculated as given below: tanθ1=45θ1=38.65°tanθ2=48θ2=26.56° Consider joint B: Take a summation of horizontal forces: ∑Fx=0600+FBCcos26.56-FBAcos38.65=0 (1) Take a summation of Vertical forces: ∑Fy=0350+FBCsin26.56+FBAsin38.65=0 (2) Solving equations (1) and (2) we get, FBC=-713.86Ib (C)FBA=-49.32Ib (C) Consider joint C: Take a summation of horizontal forces: ∑Fx=0-FCA--713.86cos26.56=0FCA=638.52Ib (T)Final Answer: The forces in each member are calculated as given below and obtained as: FBC=-652.07Ib (C)FBA=-49.32Ib (C)FCA=638.52Ib (T)