1. Determine the following conditional probabilities. Consider a bag with marbles, 3 blue marbles, 2 red marbles, and 5 green marbles. Three marbles are drawn in sequence and are taken without replacement. Reduced Fraction Reduced Fraction: i. P(2« draw: blue | 1st draw: red) = ii. P P(2“ draw: blue | 1st draw: blue) = Reduced Fraction: Reduced Fraction iii. P(3ª draw: blue | 1st draw: red, 2ª draw: blue) = i1. P P(1ª draw: blue | 1st draw: red) =

A First Course in Probability (10th Edition)
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ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
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Concept:
P(A/B) =
ONDITIONAL PROBABILITY
1. Determine the following conditional probabilities.
Consider a bag with marbles, 3 blue marbles, 2 red marbles, and 5 green marbles. Three marbles are
drawn in sequence and are taken without replacement.
Reduced Fraction
Reduced Fraction:
i. P(2d draw: blue | 1st draw: red) =
ii. P P(2d draw: blue | 1st draw: blue) =
Reduced Fraction:
Reduced Fraction
iii. P(3* draw: blue | 1st draw. red, 2d draw: blue) =
ii. P P(1* draw: blue | 1st draw: red) =
Transcribed Image Text:Concept: P(A/B) = ONDITIONAL PROBABILITY 1. Determine the following conditional probabilities. Consider a bag with marbles, 3 blue marbles, 2 red marbles, and 5 green marbles. Three marbles are drawn in sequence and are taken without replacement. Reduced Fraction Reduced Fraction: i. P(2d draw: blue | 1st draw: red) = ii. P P(2d draw: blue | 1st draw: blue) = Reduced Fraction: Reduced Fraction iii. P(3* draw: blue | 1st draw. red, 2d draw: blue) = ii. P P(1* draw: blue | 1st draw: red) =
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