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1. Determine the equation of a circle with the center at origin and a radius of 6 units? y2 35 c. x2 + y2 = 24 d. x2 + y2 = 25 a. x2 + b. X2 + y2 36 2. What is the radius of a circle given the equation x2 + y2 = 324? a. 12 %3D %3D с. 15 b. 17 d. 18 3. Find the equation of a circle with center at (-6, 4) and a radius of 12 units. a (x + 4) 2 + (y - 6) 2 = 12 b. (x - 6) 2 + (y - 4) 2 = 144 4. Which of the following is the general form of the equation (x - 2) 2 + (y - 4) 2 = c. (x + 6) 2 + (y- 4) 2 =144 d. (x + 6) 2 + (y - 4)2 12 %3D 36? a. x2 + y2 - 4x - 8y - 16 = 0 b. x2 + y2 - 2x - 8y - 16 = 0 . Given the equation x2 + y² + 12x - 2y-54 0, find the center of the equation. a (-6, 1) Determine the equation of a circle with center at (-4, 0) passes through the point ( 2,1) c. x2 + y2 - 4x - 4y - 16 = 0 d. x2 + y2 - 4x- 8y - 36 = 0 b. (-1, -6) с. (6, -1) d. (1, 6)

1. Determine the equation of a circle with the center at origin and a radius of 6 units? y2 35 c. x2 + y2 = 24 d. x2 + y2 = 25 a. x2 + b. X2 + y2 36 2. What is the radius of a circle given the equation x2 + y2 = 324? a. 12 %3D %3D с. 15 b. 17 d. 18 3. Find the equation of a circle with center at (-6, 4) and a radius of 12 units. a (x + 4) 2 + (y - 6) 2 = 12 b. (x - 6) 2 + (y - 4) 2 = 144 4. Which of the following is the general form of the equation (x - 2) 2 + (y - 4) 2 = c. (x + 6) 2 + (y- 4) 2 =144 d. (x + 6) 2 + (y - 4)2 12 %3D 36? a. x2 + y2 - 4x - 8y - 16 = 0 b. x2 + y2 - 2x - 8y - 16 = 0 . Given the equation x2 + y² + 12x - 2y-54 0, find the center of the equation. a (-6, 1) Determine the equation of a circle with center at (-4, 0) passes through the point ( 2,1) c. x2 + y2 - 4x - 4y - 16 = 0 d. x2 + y2 - 4x- 8y - 36 = 0 b. (-1, -6) с. (6, -1) d. (1, 6)

Algebra and Trigonometry (6th Edition)
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Answer number 1 to 6 pls.

Assessment Directions: Choose the letter of the correct answer and write the answers on your рaper. 1. Determine the equation of a circle with the center at origin and a radius of 6 units? a x2 + y2 = 35 b. X2 + y2 = 36 c. x2 + y2 = 24 d. x2 + y2 = 25 %3D 2. What is the radius of a circle given the equation x2 + y2 = 324? %3D a. 12 ь. 17 3. Find the equation of a circle with center at (-6, 4) and a radius of 12 units. с. 15 d. 18 a. (x + 4) 2 + (y - 6) 2 = 12 c. (x + 6) 2 + (y - 4) 2 =144 d. (x + 6) 2 + (y- 4)2 = 12 b. (x - 6) 2 + (y - 4) 2 = 144 4. Which of the following is the general form of the equation (x - 2) 2 + (y - 4) 2 = 36? a. x2 + y2 - 4x - 8y - 16 = 0 b. X2 + y2 - 2x - 8y - 16 = 0 5. Given the equation x2 + y2 + 12x- 2y- 54 0, find the center of the equation. a (-6, 1) 6. Determine the equation of a circle with center at (-4, 0 ) passes through the point ( 2,1) a. (x - 2) 2 + (y - 2)2 = 30 b. (x - 2) 2 + (x + 2) 2 = 34 c. x2 + y2 - 4x - 4y - 16 = 0 d. x2 + y2-4x - 8y -36 = 0 b. (-1, -6) с. (6, -1) d. (1, 6) c. (x + 2) 2 + (y + 2) 2 = 32 d. (x + 4) 2 + y 2 = 37 %3D
Transcribed Image Text:Assessment Directions: Choose the letter of the correct answer and write the answers on your рaper. 1. Determine the equation of a circle with the center at origin and a radius of 6 units? a x2 + y2 = 35 b. X2 + y2 = 36 c. x2 + y2 = 24 d. x2 + y2 = 25 %3D 2. What is the radius of a circle given the equation x2 + y2 = 324? %3D a. 12 ь. 17 3. Find the equation of a circle with center at (-6, 4) and a radius of 12 units. с. 15 d. 18 a. (x + 4) 2 + (y - 6) 2 = 12 c. (x + 6) 2 + (y - 4) 2 =144 d. (x + 6) 2 + (y- 4)2 = 12 b. (x - 6) 2 + (y - 4) 2 = 144 4. Which of the following is the general form of the equation (x - 2) 2 + (y - 4) 2 = 36? a. x2 + y2 - 4x - 8y - 16 = 0 b. X2 + y2 - 2x - 8y - 16 = 0 5. Given the equation x2 + y2 + 12x- 2y- 54 0, find the center of the equation. a (-6, 1) 6. Determine the equation of a circle with center at (-4, 0 ) passes through the point ( 2,1) a. (x - 2) 2 + (y - 2)2 = 30 b. (x - 2) 2 + (x + 2) 2 = 34 c. x2 + y2 - 4x - 4y - 16 = 0 d. x2 + y2-4x - 8y -36 = 0 b. (-1, -6) с. (6, -1) d. (1, 6) c. (x + 2) 2 + (y + 2) 2 = 32 d. (x + 4) 2 + y 2 = 37 %3D
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