1. Determine empirical formula and molecular formula for the compound that is 25.5% carbon, 6.38% hydrogen, and 68.1% sulfur. Its molecular mass is close to 100 grams.

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Chapter1: Chemical Foundations
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1. Determine empirical formula and molecular formula for the compound that is 25.5%
carbon, 6.38% hydrogen, and 68.1% sulfur. Its molecular mass is close to 100 grams.
2. Calculate the mass percent composition of the elements in Mg(NO3),.
% Mg =,
% N =
% 0 =
3. Determine the grams of H2O produced if you started with 33.2 g Mg(OH)2.
Mg(OH)2 + 2HCI → MgCl2 + 2H2O
33.2 g
g ?
3
4. For the reaction quantities shown below:
Identify the limiting reagent and excess reactant.
The grams of TIO2 produced
The grams of excess reactant not consumed.
TiCl4
2 H2O
TiO2 +
4 HCІ
7.14 g
2.12 g
? g
I!!
Transcribed Image Text:8:17 4 Done 1 of 21 1. Determine empirical formula and molecular formula for the compound that is 25.5% carbon, 6.38% hydrogen, and 68.1% sulfur. Its molecular mass is close to 100 grams. 2. Calculate the mass percent composition of the elements in Mg(NO3),. % Mg =, % N = % 0 = 3. Determine the grams of H2O produced if you started with 33.2 g Mg(OH)2. Mg(OH)2 + 2HCI → MgCl2 + 2H2O 33.2 g g ? 3 4. For the reaction quantities shown below: Identify the limiting reagent and excess reactant. The grams of TIO2 produced The grams of excess reactant not consumed. TiCl4 2 H2O TiO2 + 4 HCІ 7.14 g 2.12 g ? g I!!
Expert Solution
Introduction

Note: Since there are multiple sub part of the question and which one has to be solved is not given, therefore solving only first part.

Empirical formula denotes the simplest molar ratio of atoms of different type of elements present in the molecule. Whereas, molecular formula denotes the actual number of atoms present in the molecule in natural form. Sometimes molecular and empirical formula is same and sometimes its different.

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