1. Determination of Kinetic Constants in an Inhibited Enzyme Reaction. Biological oxidation of phenylacetic acid is inhibited by propionic acid present in wastewater. The following data were obtained for enzymatic oxidation of phenylacetic acid at different concentrations of propionic acid: a. What kind of inhibition is this? b. Determine Vmax, Km, and KI? Table 1 S (mM) 0.25 0.40 V (mM/1*hr), I = 0 mM 1.0 1.7 V (mM/l*hr), I = 1 mM 0.65 1.1 V (mM/1*hr), I = 2 mM | 0.55 0.9 930 1111 0.50 0.60 0.75 1.00 1.9 2.1 2.4 2.5 1.3 1.4 1.8 2.2 1.0 1.3 1.4 1.8 *mM = millimolar
1. Determination of Kinetic Constants in an Inhibited Enzyme Reaction. Biological oxidation of phenylacetic acid is inhibited by propionic acid present in wastewater. The following data were obtained for enzymatic oxidation of phenylacetic acid at different concentrations of propionic acid: a. What kind of inhibition is this? b. Determine Vmax, Km, and KI? Table 1 S (mM) 0.25 0.40 V (mM/1*hr), I = 0 mM 1.0 1.7 V (mM/l*hr), I = 1 mM 0.65 1.1 V (mM/1*hr), I = 2 mM | 0.55 0.9 930 1111 0.50 0.60 0.75 1.00 1.9 2.1 2.4 2.5 1.3 1.4 1.8 2.2 1.0 1.3 1.4 1.8 *mM = millimolar
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Transcribed Image Text:1. Determination of Kinetic Constants in an Inhibited Enzyme Reaction.
Biological oxidation of phenylacetic acid is inhibited by propionic acid present in
wastewater. The following data were obtained for enzymatic oxidation of phenylacetic acid
at different concentrations of propionic acid:
a. What kind of inhibition is this?
b. Determine Vmax, Km, and KI?
Table 1
S (mM)
0.25
0.40
0.50
0.60
0.75
1.00
V (mM/1*hr), I = 0 mM
1.0
1.7
1.9
2.1
2.4
2.5
V (mM/l*hr), I = 1 mM
0.65
1.1
1.3
1.4
1.8
2.2
V (mM/1*hr), I = 2 mM
0.55
0.9
1.0
1.3
1.4
1.8
*mM = millimolar
B) → p =
A) Non Competitive Inhibition
CsxVMax
KM + Cs + KMK₂C₁ + K₂CsC₁)
Where
KM = 1.42 & 1 = 0, & Vмax
€ 6.95, & V = -76
K₂ = 0.68 & K₁
=
1.43
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