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1. Current flows in circuit are governed by Kirchoff's laws. It states that the algebraic sum of the currents flowing into a junction of a circuit must equal to zero. From a circuit, the following equations were obtained. I + 12 – 13 = 0 21, + 513 = 6 21, – 412 = 4 Use Gauss-Seidel method in solving the currents with initial estimates of I, = 1.2, I2= -0.5 and I3= 0.8. Perform | 3 iterations. Iteration I I2 I3 Ea (I1),% Ea (I2),% Ea (I3),% 1.2 -0.5 0.8 1 2 3

1. Current flows in circuit are governed by Kirchoff's laws. It states that the algebraic sum of the currents flowing into a junction of a circuit must equal to zero. From a circuit, the following equations were obtained. I + 12 – 13 = 0 21, + 513 = 6 21, – 412 = 4 Use Gauss-Seidel method in solving the currents with initial estimates of I, = 1.2, I2= -0.5 and I3= 0.8. Perform | 3 iterations. Iteration I I2 I3 Ea (I1),% Ea (I2),% Ea (I3),% 1.2 -0.5 0.8 1 2 3

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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1. Current flows in circuit are governed by Kirchoffs laws. It states that the algebraic sum of the currents flowing into a junction of a circuit must equal to zero. From a circuit, the following equations were obtained. I + 12 – I3 = 0 211 + 513 = 6 21, – 41, = 4 Use Gauss-Seidel method in solving the currents with initial estimates of I1 = 1.2, I2= -0.5 and I3= 0.8. Perform 3 iterations. Iteration I1 I2 I3 Ea (I1),% Ea (I2),% Ea (I3),% 1.2 -0.5 0.8 1 2 3.
Transcribed Image Text:1. Current flows in circuit are governed by Kirchoffs laws. It states that the algebraic sum of the currents flowing into a junction of a circuit must equal to zero. From a circuit, the following equations were obtained. I + 12 – I3 = 0 211 + 513 = 6 21, – 41, = 4 Use Gauss-Seidel method in solving the currents with initial estimates of I1 = 1.2, I2= -0.5 and I3= 0.8. Perform 3 iterations. Iteration I1 I2 I3 Ea (I1),% Ea (I2),% Ea (I3),% 1.2 -0.5 0.8 1 2 3.
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